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A digital display records the number of operations carried out by a computer as 22x23. (a) Simplify the expression, leaving your answer in index form. (b) Hence, write the answer as an ordinary number. (c) Simplify: 54 x 54 / 53

Mathematics

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Answers

2 parts
a

2n+12^{n+1}

c

555^5

Step-by-step solution

3 steps

Huu hapa ni ufumbuzi wa swali la 22.

Part 22

A digital display records the number of operations carried out by a computer as 2n×212^n \times 2^1.

Part a

2n+12^{n+1}

Rahisisha usemi, ukiacha jibu lako katika fomu ya 'index'.

  1. Tumia sheria ya 'indices' inayosema kwamba unapozidisha namba zenye 'base' sawa, unaongeza 'powers' zake

    am×an=am+na^m \times a^n = a^{m+n}.

    2n×21=2n+12^n \times 2^1 = 2^{n+1}

    Jibu ni 2n+1\boxed{2^{n+1}}.

Part b

Kwa hivyo, andika jibu kama nambari ya kawaida.

Haiwezekani kuandika 2n+12^{n+1} kama nambari ya kawaida bila kujua thamani maalum ya 'n'.

Part c

555^5

Rahisisha: 54×5453\frac{5^4 \times 5^4}{5^3}

  1. Rahisisha nambari ya juu (numerator) kwa kutumia sheria ya 'indices' am×an=am+na^m \times a^n = a^{m+n}.

    54×54=54+4=585^4 \times 5^4 = 5^{4+4} = 5^8
  2. Rahisisha usemi mzima kwa kutumia sheria ya 'indices' inayosema kwamba unapotenganisha namba zenye 'base' sawa, unatoa 'powers' zake

    aman=am−n\frac{a^m}{a^n} = a^{m-n}.

    5853=58−3=55\frac{5^8}{5^3} = 5^{8-3} = 5^5

    Jibu ni 55\boxed{5^5}.

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