a) To establish the formula for nCr:
Step 1: Define combinations.
A combination nCr represents the number of ways to choose r items from a set of n distinct items, where the order of selection does not matter.
Step 2: Relate to permutations.
The number of permutations of r items chosen from n is given by nPr=(n−r)!n!. Since the order of the r chosen items does not matter in a combination, we divide the number of permutations by the number of ways to arrange the r items, which is r!.
Step 3: State the formula.
Therefore, the formula for nCr is:
nCr=r!nPr=r!(n−r)!n!
b) To show that 8C5=8C3:
Step 1: Calculate 8C5 using the formula nCr=r!(n−r)!n!.
8C5=5!(8−5)!8!=5!3!8!
Step 2: Calculate 8C3 using the formula.
8C3=3!(8−3)!8!=3!5!8!
Step 3: Compare the results.
Since 5!3!=3!5!, we can see that:
5!3!8!=3!5!8!
Thus, 8C5=8C3.
c) To find the values of the expressions:
i) 10!×4!14!
Step 1: Expand the factorials and simplify.
10!×4!14!=10!×(4×3×2×1)14×13×12×11×10!
Step 2: Cancel 10! and calculate the remaining terms.
=4×3×2×114×13×12×11=2414×13×12×11
Step 3: Perform the multiplication and division.
=2424024=1001
The value is 1001.
ii) 6!×3!9!
Step 1: Expand the factorials and simplify.
6!×3!9!=6!×(3×2×1)9×8×7×6!
Step 2: Cancel 6! and calculate the remaining terms.
=3×2×19×8×7=69×8×7
Step 3: Perform the multiplication and division.
=6504=84
The value is 84.
iii) 10!×10!20!
Step 1: Expand the factorials and simplify.
10!×10!20!=10!×(10×9×8×7×6×5×4×3×2×1)20×19×18×17×16×15×14×13×12×11×10!
Step 2: Cancel 10! and simplify the remaining terms by cancelling common factors.
=10×9×8×7×6×5×4×3×2×120×19×18×17×16×15×14×13×12×11
=(20/(10×2))×(18/9)×(16/8)×(15/(5×3))×(14/7)×(12/6)×19×17×13×11×(1/4)
=1×2×2×1×2×2×19×17×13×11×(1/4)
=416×19×17×13×11
Step 3: Perform the multiplication and division.
=4×19×17×13×11
=4×323×143
=4×46189
=184756
The value is 184756.
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