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A farmer wants to maximize profit from selling onions and greens. Onions yield 500,000 profit/ton and greens yield 300,000 profit/ton. The farmer has 10 hectares of land (onions: 1 ha/ton, greens: 2 h
Mathematics
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Step-by-step solution
4 stepsHere's the solution to your linear programming problem:
Task (a):
Define variables.
Let be the number of tons of onions.
Let be the number of tons of greens.Formulate the objective function.
The farmer wants to maximize profit.
Profit from onions: Ugx. 500,000 per ton.
Profit from greens: Ugx. 300,000 per ton.
The objective function to maximize is:Formulate the constraints.
- Land Constraint: The farmer has "almost ten hectares" of land. Onions need 1 hectare per ton, and greens need 2 hectares per ton.
- Labor Constraint: The farmer intends to spend "not more than 120 hours per week" on labor. Onions require 2 hours per ton, and greens require 3 hours per ton.
- Non-negativity Constraints: The number of tons of crops cannot be negative.
The required inequalities are:
Task (b):
Graph the inequalities and identify the feasible region.
To graph the inequalities, we consider their boundary lines:
- For : If , . Point: . If $y=
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