A figure consists of a large semicircle with two smaller semicircles removed from its base. The base of the large semicircle is 28 cm. Find the area of the shaded region.

The total base length of the figure is $14 \text{ cm} + 14 \text{ cm} = 28 \text{ cm}$. This is the diameter of the large semicircle.
Radius of the large semicircle, $R = \frac{28 \text{ cm}}{2} = 14 \text{ cm}$.

Each of the two smaller semicircles has a diameter of $14 \text{ cm}$.
Radius of each small semicircle, $r = \frac{14 \text{ cm}}{2} = 7 \text{ cm}$.

The formula for the area of a semicircle is $\frac{1}{2} \pi (\text{radius})^2$.
Area of large semicircle ($A_{large}$) = $\frac{1}{2} \pi R^2 = \frac{1}{2} \pi (14 \text{ cm})^2$

$$A_{large} = \frac{1}{2} \pi (196 \text{ cm}^2) = 98\pi \text{ cm}^2$$

Area of one small semicircle ($A_{small}$) = $\frac{1}{2} \pi r^2 = \frac{1}{2} \pi (7 \text{ cm})^2$

$$A_{small} = \frac{1}{2} \pi (49 \text{ cm}^2) = 24.5\pi \text{ cm}^2$$

Total area of two small semicircles ($A_{unshaded}$) = $2 \times A_{small} = 2 \times 24.5\pi \text{ cm}^2$

$$A_{unshaded} = 49\pi \text{ cm}^2$$

The shaded area is the area of the large semicircle minus the total area of the two small semicircles.
Shaded Area ($A_{shaded}$) = $A_{large} - A_{unshaded}$

$$A_{shaded} = 98\pi \text{ cm}^2 - 49\pi \text{ cm}^2$$ $$A_{shaded} = 49\pi \text{ cm}^2$$

$$A_{shaded} \approx 49 \times 3.14159 \text{ cm}^2$$ $$A_{shaded} \approx 153.94 \text{ cm}^2$$

The area of the shaded part is $\boxed{49\pi \text{ cm}^2}$ or approximately $\boxed{153.94 \text{ cm}^2}$.