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The graph below shows a patient's temperature recorded at intervals of 2 hours from 8am to 4pm. Use it to answer the questions.

Mathematics

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Answers

3 parts
b

39.0 °C\text{39.0 °C}

c

10:00 a.m.\text{10:00 a.m.}

d

37.1 °C\text{37.1 °C}

Step-by-step solution

4 steps

Hapa kuna majibu kwa maswali yako:

Part a

Joto lilikuwa sawa saa 12:00 mchana na saa 4:00 p.m.

Jibu lako la 10:00 a.m. si sahihi kwa swali hili.

Part b

39.0 °C\text{39.0 °C}

Joto la juu zaidi lilikuwa

39.0 °C\boxed{\text{39.0 °C}}

Jibu lako ni sahihi.

Part c

10:00 a.m.\text{10:00 a.m.}

Joto lilikuwa 37.5°C saa

10:00 a.m.\boxed{\text{10:00 a.m.}}

Jibu lako ni sahihi.

Part d

37.1 °C\text{37.1 °C}

Ili kukokotoa wastani wa joto la mgonjwa, tunajumlisha vipimo vyote vya joto na kugawanya kwa idadi ya vipimo.

  1. Andika vipimo vya joto kutoka kwenye grafu.

    Vipimo vya joto ni: 36.0 ∘C36.0 \,^{\circ}\text{C} (saa 8:00 a.m.), 37.5 ∘C37.5 \,^{\circ}\text{C} (saa 10:00 a.m.), 36.5 ∘C36.5 \,^{\circ}\text{C} (saa 12:00 mchana), 39.0 ∘C39.0 \,^{\circ}\text{C} (saa 2:00 p.m.), na 36.5 ∘C36.5 \,^{\circ}\text{C} (saa 4:00 p.m.).

  2. Jumlisha vipimo vyote vya joto.

    36.0+37.5+36.5+39.0+36.5=185.5 ∘C36.0 + 37.5 + 36.5 + 39.0 + 36.5 = 185.5 \,^{\circ}\text{C}

  3. Gawanya jumla kwa idadi ya vipimo (ambayo ni 5).

    Wastani wa joto=185.55\text{Wastani wa joto} = \frac{185.5}{5}

  4. Kokotoa wastani.

    Wastani wa joto=37.1 ∘C\text{Wastani wa joto} = 37.1 \,^{\circ}\text{C}

    Wastani wa joto la mgonjwa ni:

    37.1 °C\boxed{\text{37.1 °C}}
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