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A group of data entrants A, B, and C start working at 8:30 am. A takes 10 minutes per learner, B takes 15 minutes, and C takes 10 minutes. When will they all get a break together and how many learners

Mathematics

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Task (a):

  1. Determine the time taken for all data entrants to finish a learner's data simultaneously.

    Data entrant A takes 10 minutes per learner.
    Data entrant B takes 15 minutes per learner.
    Data entrant C takes 10 minutes per learner.
    To find when they all finish at the same time, we need to find the Least Common Multiple (LCM) of their individual times.

    LCM(10,15,10)=LCM(10,15)\text{LCM}(10, 15, 10) = \text{LCM}(10, 15)

    Prime factorization of 10 is 2×52 \times 5.
    Prime factorization of 15 is 3×53 \times 5.

    LCM(10,15)=2×3×5=30 minutes\text{LCM}(10, 15) = 2 \times 3 \times 5 = 30 \text{ minutes}

    So, they will all finish a batch of learners simultaneously every 30 minutes.

    a) (i) At what time will all the data entrants get a break together?
    They started working at 8:30 am. The first break will occur after 30 minutes.

    8:30 am+30 minutes=9:00 am8:30 \text{ am} + 30 \text{ minutes} = 9:00 \text{ am}

    The data entrants will get a break together at 9:00 am\boxed{\text{9:00 am}}.

    a) (ii) Obtain the number of learners whose data was captured before the first break.
    The duration before the first break is 30 minutes.
    Number of learners captured by A: 30 minutes10 minutes/learner=3 learners\frac{30 \text{ minutes}}{10 \text{ minutes/learner}} = 3 \text{ learners}
    Number of learners captured by B: 30 minutes15 minutes/learner=2 learners\frac{30 \text{ minutes}}{15 \text{ minutes/learner}} = 2 \text{ learners}
    Number of learners captured by C: 30 minutes10 minutes/learner=3 learners\frac{30 \text{ minutes}}{10 \text{ minutes/learner}} = 3 \text{ learners}
    Total number of learners captured:

    3+2+3=8 learners3 + 2 + 3 = 8 \text{ learners}

    The total number of learners whose data was captured before the first break is 8 learners\boxed{8 \text{ learners}}.

    Task (b):

  2. Identify the relevant financial information.

    School fees per learner: Ugx. 900,000.
    Cost for refreshments for guests per learner: Ugx. 5,000.
    Percentage of remaining fees for food: 40%.

    b) (i) Determine how much money the school spent on refreshments if it was based on the learners whose data was captured before the first break.
    From part (a)(ii), 8 learners had their data captured before the first break.
    Cost for refreshments per learner: Ugx. 5,000.
    Total money spent on refreshments:

    8 learners×Ugx. 5,000/learner=Ugx. 40,0008 \text{ learners} \times \text{Ugx. } 5,000/\text{learner} = \text{Ugx. } 40,000

    The school spent Ugx. 40,000\boxed{\text{Ugx. } 40,000} on refreshments.

    b) (ii) How much money did each learner pay on food.
    First, calculate the remaining fees per learner after deducting the guest refreshments.
    Remaining fees per learner = Total fees per learner - Guest refreshments per learner

    Ugx. 900,000−Ugx. 5,000=Ugx. 895,000\text{Ugx. } 900,000 - \text{Ugx. } 5,000 = \text{Ugx. } 895,000

    Next, calculate 40% of these remaining fees for food.
    Money for food per learner = 40%×Ugx. 895,00040\% \times \text{Ugx. } 895,000

    0.40×Ugx. 895,000=Ugx. 358,0000.40 \times \text{Ugx. } 895,000 = \text{Ugx. } 358,000

    Each learner paid Ugx. 358,000\boxed{\text{Ugx. } 358,000} on food.

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