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A journey consists of three parts. Part 1: 2 hours at 60 km/h. Part 2: 30 minutes at 10 km/h. Part 3: 40 minutes at an unknown speed. Calculate the total distance and total time.

Mathematics

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Answers

3 parts
a

125 km\text{125 km}

b

196 hours\frac{19}{6} \text{ hours}

c

75019 km/h\frac{750}{19} \text{ km/h}

Step-by-step solution

7 steps

Here's how to solve the problem:

Part a· 3 steps

Calculate the total distance covered in the whole journey.

  1. Calculate the distance covered in the first part of the journey.

    The formula for distance is Distance=Speed×Time\text{Distance} = \text{Speed} \times \text{Time}.

    D1=60 km/h×2 hours=120 kmD_1 = 60 \text{ km/h} \times 2 \text{ hours} = 120 \text{ km}
  2. Calculate the distance covered in the second part of the journey.

    First, convert 30 minutes to hours.

    30 minutes=3060 hours=0.5 hours30 \text{ minutes} = \frac{30}{60} \text{ hours} = 0.5 \text{ hours}

    Now, calculate the distance:

    D2=10 km/h×0.5 hours=5 kmD_2 = 10 \text{ km/h} \times 0.5 \text{ hours} = 5 \text{ km}
  3. Calculate the total distance covered.

    Dtotal=D1+D2=120 km+5 km=125 kmD_{\text{total}} = D_1 + D_2 = 120 \text{ km} + 5 \text{ km} = \boxed{\text{125 km}}

Part b

196 hours\frac{19}{6} \text{ hours}

Calculate the total time taken in the whole journey.

  1. Convert all time durations to hours.

    Time for the first part (T1T_1) = 2 hours
    Time for the rest (TrestT_{\text{rest}}) = 40 minutes =4060 hours=23 hours= \frac{40}{60} \text{ hours} = \frac{2}{3} \text{ hours}
    Time for the second part (T2T_2) = 30 minutes =3060 hours=0.5 hours=12 hours= \frac{30}{60} \text{ hours} = 0.5 \text{ hours} = \frac{1}{2} \text{ hours}

  2. Calculate the total time taken.

    Ttotal=T1+Trest+T2T_{\text{total}} = T_1 + T_{\text{rest}} + T_2 Ttotal=2 hours+23 hours+12 hoursT_{\text{total}} = 2 \text{ hours} + \frac{2}{3} \text{ hours} + \frac{1}{2} \text{ hours}

    To add these, find a common denominator, which is 6:

    Ttotal=126 hours+46 hours+36 hoursT_{\text{total}} = \frac{12}{6} \text{ hours} + \frac{4}{6} \text{ hours} + \frac{3}{6} \text{ hours} Ttotal=12+4+36 hours=196 hoursT_{\text{total}} = \frac{12 + 4 + 3}{6} \text{ hours} = \frac{19}{6} \text{ hours}

    As a decimal, this is approximately:

    Ttotal≈3.17 hoursT_{\text{total}} \approx 3.17 \text{ hours}

    So, the total time taken is 196 hours\boxed{\frac{19}{6} \text{ hours}}.

Part c

75019 km/h\frac{750}{19} \text{ km/h}

Calculate the average speed used in the whole journey.

  1. Use the total distance and total time calculated above.

    Total distance (DtotalD_{\text{total}}) = 125 km
    Total time (TtotalT_{\text{total}}) = 196\frac{19}{6} hours

  2. Calculate the average speed.

    The formula for average speed is Average Speed=Total DistanceTotal Time\text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}}.

    Average Speed=125 km196 hours\text{Average Speed} = \frac{125 \text{ km}}{\frac{19}{6} \text{ hours}} Average Speed=125×619 km/h\text{Average Speed} = 125 \times \frac{6}{19} \text{ km/h} Average Speed=75019 km/h\text{Average Speed} = \frac{750}{19} \text{ km/h}

    As a decimal, this is approximately:

    Average Speed≈39.47 km/h\text{Average Speed} \approx 39.47 \text{ km/h}

    So, the average speed is 75019 km/h\boxed{\frac{750}{19} \text{ km/h}}.

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