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The graph shows a commuter's journey to work. His journey consists of two stages of travelling, separated by a break of 30 minutes. a) What was his speed (in km/h) during the first stage of his journey? b) What was his speed (in km/h) during the second stage of his journey?

Mathematics

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Answers

2 parts
a

8 km/h\text{8 km/h}

b

10 km/h\text{10 km/h}

Step-by-step solution

8 steps

Here's how to calculate the speed for each stage of the journey from the distance-time graph. Speed is calculated as the change in distance divided by the change in time.

Part a· 4 steps

  1. Identify the distance and time for the first stage.

    The first stage of the journey starts at 07:0007:00 with 0 km0 \text{ km} distance and ends at 07:3007:30 with 4 km4 \text{ km} distance.

  2. Calculate the distance covered and time taken.

    Distance covered (Δd\Delta d) = 4 km−0 km=4 km4 \text{ km} - 0 \text{ km} = 4 \text{ km}
    Time taken (Δt\Delta t) = 07:30−07:00=30 minutes07:30 - 07:00 = 30 \text{ minutes}

  3. Convert time to hours.

    30 minutes=3060 hours=0.5 hours30 \text{ minutes} = \frac{30}{60} \text{ hours} = 0.5 \text{ hours}
  4. Calculate the speed for the first stage.

    Speed=ΔdΔt=4 km0.5 hours=8 km/h\text{Speed} = \frac{\Delta d}{\Delta t} = \frac{4 \text{ km}}{0.5 \text{ hours}} = 8 \text{ km/h}

    The speed during the first stage was 8 km/h\boxed{\text{8 km/h}}.

Part b

10 km/h\text{10 km/h}

  1. Identify the distance and time for the second stage.

    The journey has a break from 07:3007:30 to 08:0008:00. The second stage of travelling starts at 08:0008:00 with 4 km4 \text{ km} distance and ends at 08:3008:30 with 9 km9 \text{ km} distance.

  2. Calculate the distance covered and time taken.

    Distance covered (Δd\Delta d) = 9 km−4 km=5 km9 \text{ km} - 4 \text{ km} = 5 \text{ km}
    Time taken (Δt\Delta t) = 08:30−08:00=30 minutes08:30 - 08:00 = 30 \text{ minutes}

  3. Convert time to hours.

    30 minutes=3060 hours=0.5 hours30 \text{ minutes} = \frac{30}{60} \text{ hours} = 0.5 \text{ hours}
  4. Calculate the speed for the second stage.

    Speed=ΔdΔt=5 km0.5 hours=10 km/h\text{Speed} = \frac{\Delta d}{\Delta t} = \frac{5 \text{ km}}{0.5 \text{ hours}} = 10 \text{ km/h}

    The speed during the second stage was 10 km/h\boxed{\text{10 km/h}}.

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