The distance-time graph shows the distance travelled by a car from 1400 to 1700 hours. (a) Calculate the speed at 1630 hours. (b) Represent the distance-time graph above on a speed-time graph.

Mathematics
The distance-time graph shows the distance travelled by a car from 1400 to 1700 hours. (a) Calculate the speed at 1630 hours. (b) Represent the distance-time graph above on a speed-time graph.

ScanSolve AI Answer

a) Calculate the speed at 16:30 hours.

Step 1: Understand that speed on a distance-time graph is represented by the gradient of the line. The time 16:30 hours falls within the segment of the graph from 15:00 to 17:00.

Step 2: Identify the coordinates for this segment. At t1=15:00t_1 = 15:00 hours, the distance d1=60 kmd_1 = 60 \text{ km}. At t2=17:00t_2 = 17:00 hours, the distance d2=90 kmd_2 = 90 \text{ km}.

Step 3: Calculate the speed (gradient) for this segment. Speed=ChangeindistanceChangeintime=d2d1t2t1\text{Speed} = \frac{Change in distance}{Change in time} = \frac{d_2 - d_1}{t_2 - t_1} Speed=90km60km17:0015:00\text{Speed} = \frac{90 km - 60 km}{17:00 - 15:00} Speed=30km2hours\text{Speed} = \frac{30 km}{2 hours} Speed=15 km/h\text{Speed} = 15 \text{ km/h} Since this segment is a straight line, the speed is constant throughout this interval.

The speed at 16:30 hours is 15km/h\boxed{15 km/h}.

b) Represent the distance-time graph above on a speed-time graph.

Step 1: Analyze the speed for each segment of the distance-time graph. Segment 1 (from 14:00 to 15:00): Time interval = 15:0014:00=1 hour15:00 - 14:00 = 1 \text{ hour}. Distance covered = 60km0km=60 km60 km - 0 km = 60 \text{ km}. Speed = 60km1hour=60 km/h\frac{60 km}{1 hour} = 60 \text{ km/h}.

Segment 2 (from 15:00 to 17:00): Time interval = 17:0015:00=2 hours17:00 - 15:00 = 2 \text{ hours}. Distance covered = 90km60km=30 km90 km - 60 km = 30 \text{ km}. Speed = 30km2hours=15 km/h\frac{30 km}{2 hours} = 15 \text{ km/h}.

Step 2: Plot these constant speeds on the speed-time graph. The x-axis of the speed-time graph represents time in hours, starting from 0 (which corresponds to 14:00).

  • From t=0t=0 hours (14:00) to t=1t=1 hour (15:00), the speed is 60 km/h60 \text{ km/h}. Draw a horizontal line at 60 km/h60 \text{ km/h} from t=0t=0 to t=1t=1.
  • From t=1t=1 hour (15:00) to t=3t=3 hours (17:00), the speed is 15 km/h15 \text{ km/h}. Draw a horizontal line at 15 km/h15 \text{ km/h} from t=1t=1 to t=3t=3.

The speed-time graph will look like this:

\begin{tikzpicture}[scale=0.8] \draw[->] (0,0) -- (4.5,0) node[below] {time (hours)}; \draw[->] (0,0) -- (0,4.5) node[left] {speed (km/h)}; \foreach \x in {0,1,2,3,4} \draw (\x,0) node[below] {\x}; \foreach \y in {0,20,40,60,80} \draw (0,\y/20*4) node[left] {\y}; \draw[dashed, gray] (0,1.2) -- (4,1.2); % 15 km/h line \draw[dashed, gray] (0,2.4) -- (4,2.4); % 30 km/h line \draw[dashed, gray] (0,3.6) -- (4,3.6); % 60 km/h line \draw[thick, blue] (0,3.6) -- (1,3.6); % First segment: 60 km/h for 1 hour \draw[thick, blue] (1,0.9) -- (3,0.9); % Second segment: 15 km/h for 2 hours \draw[fill=black] (0,3.6) circle (1.5pt); \draw[fill=black] (1,3.6) circle (1.5pt); \draw[fill=black] (1,0.9) circle (1.5pt); \draw[fill=black] (3,0.9) circle (1.5pt); \end{tikzpicture}

The graph should show a horizontal line at 60 km/h60 \text{ km/h} from t=0t=0 to t=1t=1 hour, and another horizontal line at 15 km/h15 \text{ km/h} from t=1t=1 to t=3t=3 hours.

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