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A ladder 13m long when set against the wall of a house, just reaches a window at a height of 12m from the ground. How far is the ladder away from the house?

Mathematics

ScanSolve AI Answer

Answer

5 m\text{5 m}

Step-by-step solution

3 steps
  1. Identify the known values and the unknown.

    The ladder, the wall, and the ground form a right-angled triangle.
    The length of the ladder is the hypotenuse, c=13c = 13 m.
    The height the ladder reaches on the wall is one leg, a=12a = 12 m.
    The distance of the ladder's foot from the house is the other leg, bb, which we need to find.

  2. Apply the Pythagorean theorem.

    The Pythagorean theorem states that a2+b2=c2a^2 + b^2 = c^2.
    Substitute the given values into the formula:

    122+b2=13212^2 + b^2 = 13^2
  3. Solve for bb.

    144+b2=169144 + b^2 = 169

    Subtract 144 from both sides:

    b2=169−144b^2 = 169 - 144 b2=25b^2 = 25

    Take the square root of both sides:

    b=25b = \sqrt{25} b=5 mb = 5 \text{ m}

    The ladder is 5 m\boxed{\text{5 m}} away from the foot of the house.

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