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A loan of Rs. 2,00,000 was taken. The annual compound interest rate is 7%. The total amount repaid is Rs. 2,28,980. a) How much interest did Ramesh pay? b) For how many years did Ramesh use the loan?

Mathematics

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Answers

2 parts
a

Rs. 28,980\text{Rs. } 28,980

b

2 वर्ष2 \text{ वर्ष}

Step-by-step solution

3 steps

यहाँ प्रश्न २ को समाधान छ:

दिइएको जानकारी:
सावाँ (Principal), P=Rs. 2,00,000P = \text{Rs. } 2,00,000
बार्षिक चक्रीय ब्याजदर (Annual compound interest rate), R=7%R = 7\%
सावाँ र ब्याज सहित फिर्ता गरेको रकम (Total amount repaid), A=Rs. 2,28,980A = \text{Rs. } 2,28,980

Part a· 1 step

रमेशले ब्याजमात्र कति बुझाएछन् ?

ब्याज (Interest), I=A−PI = A - P

  1. ब्याज पत्ता लगाउनुहोस्।

    I=2,28,980−2,00,000I = 2,28,980 - 2,00,000 I=28,980I = 28,980

    रमेशले बुझाएको ब्याज Rs. 28,980\boxed{\text{Rs. } 28,980} हो।

Part b

2 वर्ष2 \text{ वर्ष}

रमेशले उक्त ऋण कति वर्षको लागि प्रयोग गरेछन् ?

चक्रीय मिश्रधन (Compound Amount) को सूत्र प्रयोग गर्नुहोस्:

A=P(1+R100)TA = P \left(1 + \frac{R}{100}\right)^T

जहाँ TT समय (वर्षमा) हो।

  1. दिएको मानहरू सूत्रमा राख्नुहोस्।

    2,28,980=2,00,000(1+7100)T2,28,980 = 2,00,000 \left(1 + \frac{7}{100}\right)^T 2,28,980=2,00,000(1+0.07)T2,28,980 = 2,00,000 \left(1 + 0.07\right)^T 2,28,980=2,00,000(1.07)T2,28,980 = 2,00,000 \left(1.07\right)^T
  2. TT को मान पत्ता लगाउनुहोस्।

    2,28,9802,00,000=(1.07)T\frac{2,28,980}{2,00,000} = (1.07)^T 1.1449=(1.07)T1.1449 = (1.07)^T

    अब, 1.07 को कुन घात 1.1449 हुन्छ पत्ता लगाउनुहोस्।

    (1.07)1=1.07(1.07)^1 = 1.07 (1.07)2=1.07×1.07=1.1449(1.07)^2 = 1.07 \times 1.07 = 1.1449

    तसर्थ, T=2T = 2 वर्ष।
    रमेशले उक्त ऋण 2 वर्ष\boxed{2 \text{ वर्ष}} को लागि प्रयोग गरेछन्।

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