A metallic sphere is dropped into a cylindrical container of radius 7 cm, causing the water level to rise by 7.5 cm. What is the volume of water displaced?

Here are the solutions to questions 2 and 4.

Question 2: Metallic sphere in cylindrical container

Step 1: Calculate the volume of water displaced.
The volume of water displaced is equal to the volume of a cylinder with the given rise in height and the base radius of the container.
The volume of a cylinder is given by $V = \pi R^2 h$.
Given: $R = 7$ cm, $h = 7.5$ cm.

$$V_{displaced} = \pi (7 \text{ cm})^2 (7.5 \text{ cm})$$ $$V_{displaced} = \pi (49 \text{ cm}^2) (7.5 \text{ cm})$$