A metallic sphere is dropped into a cylindrical container of radius 7 cm, causing the water level to rise by 7.5 cm. What is the volume of water displaced?

April 16, 2026Mathematics

ScanSolve AI Answer

April 16, 2026

Answer

\pi R^2 h$.

Here are the solutions to questions 2 and 4.

Question 2: Metallic sphere in cylindrical container

Step 1: Calculate the volume of water displaced. The volume of water displaced is equal to the volume of a cylinder with the given rise in height and the base radius of the container. The volume of a cylinder is given by $V = \pi R^2 h$ . Given: $R = 7$ cm, $h = 7.5$ cm. $V_{displaced} = \pi (7 cm)^2 (7.5 cm)$ $V_{displaced} = \pi (49 cm^2) (7.5 cm)$

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Metallic sphere in cylindrical container Step 1: Calculate the volume of water displaced.

Asked on April 16, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on April 16, 2026

Here are the solutions to questions 2 and 4. Question 2: Metallic sphere in cylindrical container Step 1: Calculate the volume of water displaced. The volume of water displaced is equal to the volume of a cylinder with the given rise in height and the base radius of the container. The volume of a cylinder is given by V = R^2 h. Given: R = 7 cm, h = 7.5 cm. V_displaced = (7 cm)^2 (7.5 cm) V_displaced = (49 cm^2) (7.5 cm)