A municipality supplies water to 108 households. 6 tanks are installed, each costing R4 950.00. The diameter of each tank is 260 cm. Calculate: 25.1.1 households per tank, 25.1.2 total cost of tanks,

Total households = 108
Total tanks = 6

Each tank is shared by $\boxed{\text{18 households}}$.

25.1.2

Cost per tank = R4 950.00
Number of tanks = 6

The municipality paid $\boxed{\text{R29 700.00}}$ for the tanks.

25.1.3

Diameter = $260 \text{ cm}$
Radius $r = \frac{\text{Diameter}}{2} = \frac{260 \text{ cm}}{2} = 130 \text{ cm}$

Area of base $= \pi r^2$
$\pi = 3.142$

The area of the base of one tank is $\boxed{\text{53109.8 cm}^2}$.

25.1.4

Area of base $= 53109.8 \text{ cm}^2$
Height $= 418 \text{ cm}$

Volume = Area $\times$ height

Since $1 \text{ m} = 100 \text{ cm}$, then $1 \text{ m}^3 = (100 \text{ cm})^3 = 1,000,000 \text{ cm}^3$.

The volume of one tank is approximately $\boxed{\text{22.21 m}^3}$.

25.1.5

Volume $= 22.2058924 \text{ m}^3$

$1 \text{ m}^3 = 1000 \text{ L}$

The tank will hold approximately $\boxed{\text{22205.89 L}}$ of water.