A packet of sweets is shared between Amina, Pauline and Sharon in the ratio 2:3:5. If Pauline received 12 sweets, how many did Sharon receive?

The ratio for Amina : Pauline : Sharon is $2:3:5$.
Pauline's share corresponds to 3 parts of the ratio.
Given that Pauline received 12 sweets, we can find the value of one part:

$$3 \text{ parts} = 12 \text{ sweets}$$ $$1 \text{ part} = \frac{12}{3} = 4 \text{ sweets}$$

Sharon's share corresponds to 5 parts of the ratio.

$$\text{Sharon's sweets} = 5 \text{ parts} \times 4 \text{ sweets/part}$$ $$\text{Sharon's sweets} = 20 \text{ sweets}$$

Sharon received $\boxed{20 \text{ sweets}}$.

3) A right circular cone has a base diameter of 12 cm and a height of 8 cm. Find the total surface area of the cone, leaving your answer to the nearest unit. Take $\pi = \frac{22}{7}$.

The base diameter is $12 \text{ cm}$, so the radius $r = \frac{12}{2} = 6 \text{ cm}$.
The height $h = 8 \text{ cm}$.
The slant height $l$ can be found using the Pythagorean theorem:

$$l = \sqrt{r^2 + h^2}$$ $$l = \sqrt{6^2 + 8^2}$$ $$l = \sqrt{36 + 64}$$ $$l = \sqrt{100}$$ $$l = 10 \text{ cm}$$

The area of the circular base is $A_{base} = \pi r^2$.

$$A_{base} = \frac{22}{7} \times (6)^2$$ $$A_{base} = \frac{22}{7} \times 36$$ $$A_{base} = \frac{792}{7} \approx 113.14 \text{ cm}^2$$

The lateral surface area is $A_{lateral} = \pi r l$.

$$A_{lateral} = \frac{22}{7} \times 6 \times 10$$ $$A_{lateral} = \frac{22}{7} \times 60$$ $$A_{lateral} = \frac{1320}{7} \approx 188.57 \text{ cm}^2$$

The total surface area (TSA) is the sum of the base area and the lateral surface area.

$$TSA = A_{base} + A_{lateral}$$ $$TSA = \frac{792}{7} + \frac{1320}{7}$$ $$TSA = \frac{2112}{7}$$ $$TSA \approx 301.71 \text{ cm}^2$$

Rounding to the nearest unit, the total surface area is $\boxed{302 \text{ cm}^2}$.

4) Complete the logic table.

P	Q	~Q	P ^ ~Q	P v (P ^ ~Q)
T	T	F	F	T
T	F	T	T	T
F	T	F	F	F
F	F	T	F	F

The completed logic table is shown above.