A parabola f(x) has its axis of symmetry at x = 1. One x-intercept is A(-2; 0). Determine the coordinates of the other x-intercept, B.

The axis of symmetry for the parabola $f(x)$ is given as $x=1$.
One x-intercept is $A(-2; 0)$. Let the other x-intercept be $B(x_B; 0)$.
The x-coordinate of the axis of symmetry is the midpoint of the x-intercepts:

$$\frac{x_A + x_B}{2} = 1$$ $$\frac{-2 + x_B}{2} = 1$$ $$-2 + x_B = 2$$ $$x_B = 4$$

The coordinates of B are $\boxed{\mathbf{(4; 0)}}$.