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Find the coordinates of A, the x-intercepts of the parabola, and the other intersection point C of the parabola y = x2 − 6x + 8 and the line y = 3x − 6.

Mathematics

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4 parts
a

A(2,0)\text{A}(2, 0)

b

(2,0) and (4,0)(2, 0) \text{ and } (4, 0)

c

C(7,15)\text{C}(7, 15)

d
5

Step-by-step solution

12 steps

Here are the calculations for each part:

The given functions are:

  1. Parabola: y=x2−6x+8y = x^2 - 6x + 8
  2. Line: y−3x+6=0  ⟹  y=3x−6y - 3x + 6 = 0 \implies y = 3x - 6

Part a· 5 steps

Coordinates of A

Point A is an intersection of the parabola and the line. To find the intersection points, set the yy-values equal.

  1. Set the equations equal to each other.

    x2−6x+8=3x−6x^2 - 6x + 8 = 3x - 6
  2. Rearrange the equation into a standard quadratic form.

    x2−6x−3x+8+6=0x^2 - 6x - 3x + 8 + 6 = 0 x2−9x+14=0x^2 - 9x + 14 = 0
  3. Factor the quadratic equation.

    (x−2)(x−7)=0(x - 2)(x - 7) = 0
  4. Solve for xx.

    x=2orx=7x = 2 \quad \text{or} \quad x = 7

    From the graph, point A is the intersection with the smaller xx-coordinate. So, xA=2x_A = 2.

  5. Substitute xA=2x_A = 2 into the linear equation to find yAy_A.

    yA=3(2)−6y_A = 3(2) - 6 yA=6−6y_A = 6 - 6 yA=0y_A = 0

    The coordinates of A are (2,0)(2, 0).

    A(2,0)\boxed{\text{A}(2, 0)}

Part b

(2,0) and (4,0)(2, 0) \text{ and } (4, 0)

X-intercepts of the graph of the function y=x2−6x+8y = x^2 - 6x + 8

X-intercepts occur when y=0y = 0.

  1. Set the function equal to zero.

    x2−6x+8=0x^2 - 6x + 8 = 0
  2. Factor the quadratic equation.

    (x−2)(x−4)=0(x - 2)(x - 4) = 0
  3. Solve for xx.

    x=2orx=4x = 2 \quad \text{or} \quad x = 4

    The x-intercepts are (2,0)(2, 0) and (4,0)(4, 0).

    (2,0) and (4,0)\boxed{(2, 0) \text{ and } (4, 0)}

Part c

C(7,15)\text{C}(7, 15)

Coordinates of point C

Point C is the other intersection of the parabola and the line. From part a), the xx-coordinates of the intersection points are x=2x = 2 and x=7x = 7. Since A has x=2x=2, C must have x=7x=7.

  1. Use xC=7x_C = 7.

  2. Substitute xC=7x_C = 7 into the linear equation to find yCy_C.

    yC=3(7)−6y_C = 3(7) - 6 yC=21−6y_C = 21 - 6 yC=15y_C = 15

    The coordinates of C are (7,15)(7, 15).

    C(7,15)\boxed{\text{C}(7, 15)}

Part d5

Average rate of change for the function y=x2−6x+8y = x^2 - 6x + 8 between points B and C

The average rate of change between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by y2−y1x2−x1\frac{y_2 - y_1}{x_2 - x_1}.

  1. Identify the coordinates of points B and C.

    From part b), point B is the other x-intercept, so B(4,0)\text{B}(4, 0).
    From part c), point C is (7,15)(7, 15).

  2. Apply the average rate of change formula.

    Average rate of change=yC−yBxC−xB\text{Average rate of change} = \frac{y_C - y_B}{x_C - x_B} Average rate of change=15−07−4\text{Average rate of change} = \frac{15 - 0}{7 - 4} Average rate of change=153\text{Average rate of change} = \frac{15}{3} Average rate of change=5\text{Average rate of change} = 5

    The average rate of change is 5.

    5\boxed{5}
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