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A rectangular prism has a base area of 24 cm² and a height of 5 cm. Calculate its volume. A swimming pool in the shape of a rectangular prism has a volume of 600 m³. The length is 20 m and the width i

Mathematics

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11. A rectangular prism has a base area of 24 cm224 \text{ cm}^2 and a height of 5 cm5 \text{ cm}. Calculate the volume of the prism using the formula: Volume = Base Area ×\times Height.

  1. Use the given formula for the volume of a prism.

    Volume=Base Area×Height\text{Volume} = \text{Base Area} \times \text{Height}
  2. Substitute the given values into the formula.

    Volume=24 cm2×5 cm\text{Volume} = 24 \text{ cm}^2 \times 5 \text{ cm}
  3. Perform the multiplication.

    Volume=120 cm3\text{Volume} = 120 \text{ cm}^3

    The volume of the prism is 120 cm3\boxed{\text{}120 \text{ cm}^3\text{}}

    12. A swimming pool in the shape of a rectangular prism has a volume of 600 cubic metres600 \text{ cubic metres}. The length is 20 metres20 \text{ metres} and the width is 15 metres15 \text{ metres}.

    a) Determine the depth of the pool.

  4. The volume of a rectangular prism is given by the formula

    Volume=Length×Width×Depth\text{Volume} = \text{Length} \times \text{Width} \times \text{Depth}.
    We are given the volume, length, and width, and need to find the depth.

    600 m3=20 m×15 m×Depth600 \text{ m}^3 = 20 \text{ m} \times 15 \text{ m} \times \text{Depth}
  5. Multiply the length and width.

    600 m3=300 m2×Depth600 \text{ m}^3 = 300 \text{ m}^2 \times \text{Depth}
  6. Divide the volume by the product of length and width to find the depth.

    Depth=600 m3300 m2\text{Depth} = \frac{600 \text{ m}^3}{300 \text{ m}^2} Depth=2 m\text{Depth} = 2 \text{ m}

    The depth of the pool is 2 m\boxed{\text{}2 \text{ m}\text{}}

    b) Explain how you used the volume formula to find the depth.

    I used the formula for the volume of a rectangular prism, Volume=Length×Width×Depth\text{Volume} = \text{Length} \times \text{Width} \times \text{Depth}. I substituted the known values for the volume, length, and width, and then rearranged the formula to solve for the unknown depth by dividing the volume by the product of the length and width.

    c) If the pool needs to be drained and refilled, and it takes 2 hours to fill 100 cubic metres, how long will it take to fill the entire pool? Show your working.

  7. Determine the total volume of the pool, which is 600 m3600 \text{ m}^3.

    We are given that it takes 2 hours to fill 100 m3100 \text{ m}^3.

  8. Calculate how many 100 m3100 \text{ m}^3 segments are in the total volume.

    Number of segments=Total VolumeVolume per segment\text{Number of segments} = \frac{\text{Total Volume}}{\text{Volume per segment}} Number of segments=600 m3100 m3\text{Number of segments} = \frac{600 \text{ m}^3}{100 \text{ m}^3} Number of segments=6\text{Number of segments} = 6
  9. Multiply the number of segments by the time it takes to fill one segment.

    Total time=6×2 hours\text{Total time} = 6 \times 2 \text{ hours} Total time=12 hours\text{Total time} = 12 \text{ hours}

    It will take 12 hours\boxed{\text{}12 \text{ hours}\text{}} to fill the entire pool.

    13. A school collected data on student attendance over a term. The data shows (in percentages): 95, 92, 88, 95, 90, 87, 95, 91.

    a) Calculate the mean, median, and mode for this data.

  10. Order the data from least to greatest

    87, 88, 90, 91, 92, 95, 95, 95.
    There are n=8n=8 data points.

  11. Calculate the mean.

    Mean=87+88+90+91+92+95+95+958\text{Mean} = \frac{87+88+90+91+92+95+95+95}{8} Mean=7338\text{Mean} = \frac{733}{8} Mean=91.625\text{Mean} = 91.625
  12. Calculate the median.

    Since there are 8 data points (an even number), the median is the average of the two middle values (the 4th and 5th values).
    The ordered data is: 87, 88, 90, 91, 92, 95, 95, 95.

    Median=91+922\text{Median} = \frac{91+92}{2} Median=1832\text{Median} = \frac{183}{2} Median=91.5\text{Median} = 91.5
  13. Calculate the mode.

    The mode is the value that appears most frequently.
    In the data set (87, 88, 90, 91, 92, 95, 95, 95), the value 95 appears three times, which is more than any other value.

    Mode=95\text{Mode} = 95

    The mean is 91.625\boxed{\text{}91.625\text{}}, the median is 91.5\boxed{\text{}91.5\text{}}, and the mode is 95\boxed{\text{}95\text{}}

    b) Analyse which measure of central tendency best represents the typical attendance rate.

    The median or the mean would best represent the typical attendance rate. The mode (95%) is the most frequent attendance, but it might not be typical if other values are spread out. The mean (91.625%) gives an average, while the median (91.5%) represents the middle value, less affected by extreme values if they were present. Given the data, all three are quite close.

    c) Justify your choice with reference to the data.

    I would choose the median (91.5%) as the best representation. The data set is fairly symmetrical without extreme outliers, and the median is robust to any potential skewness or outliers. While the mean (91.625%) is very close, the median provides a clear central point of the ordered data. The mode (95%) is the most frequent, but it's at the higher end of the data, and not necessarily the "typical" central value.

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