A survey of 200 students found that 75 offered MTH 101, 86 offered PHY 101, and 100 offered CS 101. If 28 offered MTH 101 and PHY 101, 22 offered MTH 101 and CS 101, and 26 offered PHY 101 and CS 101,

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Asked on May 1, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

Accepted Answer · 2026-05-01T08:30:10.899Z

Here's a step-by-step solution to the problem. Let N be the total number of students. Let M be the set of students who offered MTH 101. Let P be the set of students who offered PHY 101. Let C be the set of students who offered CS 101. Given information: N = 200 |M| = 75 |P| = 86 |C| = 100 |M P| = 28 |M C| = 22 $|P C| = 26

Accepted Answer · 2026-05-01T08:30:10.899Z

Here's a step-by-step solution to the problem. Let N be the total number of students. Let M be the set of students who offered MTH 101. Let P be the set of students who offered PHY 101. Let C be the set of students who offered CS 101. Given information: N = 200 |M| = 75 |P| = 86 |C| = 100 |M P| = 28 |M C| = 22 $|P C| = 26

A survey of 200 students found that 75 offered MTH 101, 86 offered PHY 101, and 100 offered CS 101. If 28 offered MTH 101 and PHY 101, 22 offered MTH 101 and CS 101, and 26 offered PHY 101 and CS 101,

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A survey of 200 students found that 75 offered MTH 101, 86 offered PHY 101, and 100 offered CS 101. If 28 offered MTH 101 and PHY 101, 22 offered MTH 101 and CS 101, and 26 offered PHY 101 and CS 101,

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