A survey of 40 houses revealed that 26 receive The Graphic and 24 receive The Times. 10 houses receive both. How many houses receive only The Times?

The formula is $n(G \cup T) = n(G) + n(T) - n(G \cap T)$.
Substitute the given values:

$$40 = 26 + 24 - n(G \cap T)$$ $$40 = 50 - n(G \cap T)$$ $$n(G \cap T) = 50 - 40$$ $$n(G \cap T) = 10$$

So, 10 houses receive both Graphic and Times.

The number of houses receiving Times only is $n(T) - n(G \cap T)$.

$$n(\text{Times only}) = 24 - 10$$ $$n(\text{Times only}) = 14$$

The number of houses which receive Times only is $\text{14}$.