A survey was conducted about visitors' drink preferences. 20 visitors were served Pepsi, 12 were served Mirinda only, h+5 were served both Pepsi and Mirinda, and 2h were served neither. Find the numbe

The problem states:

• Total visitors served with Pepsi, $n(P) = 20$.
• Visitors served with Mirinda only, $n(M \text{ only}) = 12$.
• Visitors served with both Pepsi and Mirinda, $n(P \cap M) = h+5$.
• Visitors served with other drinks (neither P nor M), $n((P \cup M)') = 2h$.

The Venn diagram shows $n(P)=2$. We will assume this is a typo and use the value from the text, $n(P)=20$, as it is more consistent with typical problem values and avoids negative counts for $h$.

The number of visitors who had Pepsi only is the total number of Pepsi drinkers minus those who had both Pepsi and Mirinda.

$$n(P \text{ only}) = n(P) - n(P \cap M)$$ $$n(P \text{ only}) = 20 - (h+5)$$ $$n(P \text{ only}) = 20 - h - 5$$ $$n(P \text{ only}) = 15 - h$$

Based on the information, the completed Venn diagram would have the following values in its respective regions:

• Number of visitors who had Pepsi only: $\boxed{15 - h}$
• Number of visitors who had Mirinda only: $\boxed{12}$
• Number of visitors who had both Pepsi and Mirinda: $\boxed{h+5}$
• Number of visitors who had other drinks (neither P nor M): $\boxed{2h}$