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In a party with guests who took Mirinda and Fanta, let k be the number of guests who took only Mirinda. If 5 guests took both Mirinda and Fanta, and the total number of guests who took Mirinda is 2k-1

Mathematics

ScanSolve AI Answer

Answer

15

Step-by-step solution

3 steps
  1. Set up the equation for N(M)N(M).

    From the Venn diagram, the number of guests who took Mirinda, N(M)N(M), is the sum of those who took only Mirinda and those who took both Mirinda and Fanta.

    N(M)=k+5N(M) = k + 5

    We are also given the expression for N(M)N(M) as 2k−102k - 10.
    Therefore, we can equate the two expressions for N(M)N(M):

    k+5=2k−10k + 5 = 2k - 10
  2. Solve the equation for kk.

    Subtract kk from both sides of the equation:

    5=2k−k−105 = 2k - k - 10 5=k−105 = k - 10

    Add 10 to both sides of the equation:

    5+10=k5 + 10 = k 15=k15 = k
  3. State the value of kk.

    The value of kk is 15.

    We can also check the values for the regions:
    Only Mirinda: k=15k = 15
    Only Fanta: K−6=15−6=9K-6 = 15-6 = 9
    Both: 5
    Neither: 7

    Total N(M)=k+5=15+5=20N(M) = k+5 = 15+5 = 20.
    Using the given formula N(M)=2k−10=2(15)−10=30−10=20N(M) = 2k-10 = 2(15)-10 = 30-10 = 20. This matches.

    The value of kk is 15\boxed{15}.

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