A tailor is sewing beads on a dress. On the first day, she sews 5 beads. Each day after that, she sews 3 more…

Question

A tailor is sewing beads on a dress. On the first day, she sews 5 beads. Each day after that, she sews 3 more beads than 8th day ? Show your working.

ScanSolve AI Tutor · Accepted Answer

This problem describes an arithmetic sequence because the number of beads sewn increases by a constant amount each day.

Identify the first term ( $a_1$ ) and the common difference ( $d$ ).
The tailor sews 5 beads on the first day, so $a_1 = 5$ .
Each day after that, she sews 3 more beads than the previous day, so the common difference $d = 3$ .
Use the formula for the $n$ -th term of an arithmetic sequence.
The formula is $a_n = a_1 + (n-1)d$ , where $a_n$ is the $n$ -th term, $a_1$ is the first term, $n$ is the term number, and $d$ is the common difference.
Substitute the values to find the number of beads on the 8th day ( $n=8$ ).
$a_8 = 5 + (8-1)3$ $a_8 = 5 + (7)3$
Calculate the value.
$a_8 = 5 + 21$ $a_8 = 26$
The tailor sews 26 beads on the 8th day.

The final answer is $26 \text{ beads}$ .

A tailor is sewing beads on a dress. On the first day, she sews 5 beads. Each day after that, she sews 3 more beads than 8th day ? Show your working.