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A tailor makes shirts and dresses. It takes 6 hours to make a shirt and 4 hours to make a dress. The tailor spends at least 240 hours. The labour cost of making a shirt is Sh. 60 and that of a dress i

Mathematics

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Step-by-step solution

4 steps

Let xx be the number of shirts and yy be the number of dresses.

a) Write down four inequalities representing the information above.

  1. Formulate the inequality for the total time spent.

    A tailor spends 6 hours to make a shirt and 4 hours to make a dress. The tailor takes at least 240 hours.
    Total time: 6x+4y6x + 4y.
    "At least 240 hours" means greater than or equal to 240.

    6x+4y≥2406x + 4y \ge 240

    Divide by 2 to simplify:

    3x+2y≥120\boxed{3x + 2y \ge 120}
  2. Formulate the inequality for the total labour cost.

    The labour cost of making a shirt is Sh. 60 and that of a dress is Sh. 70. The total labour cost should not exceed Sh. 4,200.
    Total labour cost: 60x+70y60x + 70y.
    "Should not exceed Sh. 4,200" means less than or equal to 4,200.

    60x+70y≤420060x + 70y \le 4200

    Divide by 10 to simplify:

    6x+7y≤420\boxed{6x + 7y \le 420}
  3. Formulate the inequality for the number of shirts.

    The tailor must make at least 20 shirts.
    "At least 20 shirts" means greater than or equal to 20.

    x≥20\boxed{x \ge 20}
  4. Formulate the inequality for the number of dresses.

    The tailor must make more than 16 dresses.
    "More than 16 dresses" means strictly greater than 16.

    y>16\boxed{y > 16}

    The four inequalities are:

    1. 3x+2y≥1203x + 2y \ge 120
    2. 6x+7y≤4206x + 7y \le 420
    3. x≥20x \ge 20
    4. y>16y > 16
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