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A tangent BE is drawn at B to a circle ABCD. AB is a chord such that the angle ABF = 50 degrees. Find the angle ACB.

Mathematics

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The angle between a tangent and a chord through the point of contact is equal to the angle in the alternate segment. This is the Alternate Segment Theorem.
Here, BE‾\overline{BE} is the tangent at BB, and AB‾\overline{AB} is a chord.
The angle ∠ABF=50∘\angle ABF = 50^\circ is the angle between the tangent BE‾\overline{BE} and the chord AB‾\overline{AB}.
The angle in the alternate segment subtended by chord AB‾\overline{AB} is ∠ACB\angle ACB.
Therefore, by the Alternate Segment Theorem:

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