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A tank has a capacity of 2000 litres. Tap K can fill the tank in 5 minutes and Tap P can fill the tank in 10 minutes. How much water does Tap K and Tap P fill in one minute respectively?

Mathematics

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Here's the solution to the problem:

Given:
Tank capacity = 2000 litres
Tap K fills the tank in 5 minutes.
Tap P fills the tank in 10 minutes.

Capacity put in the tank by tap K in one minute:

  1. Calculate the rate of tap K.

    Tap K fills 2000 litres in 5 minutes.

    Rate of K=Total capacityTime taken by K=2000 litres5 minutes\text{Rate of K} = \frac{\text{Total capacity}}{\text{Time taken by K}} = \frac{2000 \text{ litres}}{5 \text{ minutes}} Rate of K=400 litres/minute\text{Rate of K} = 400 \text{ litres/minute}

    Tap K puts 400 litres into the tank in one minute.

    400 litres\boxed{400 \text{ litres}}

    Capacity filled by tap P in the tank in one minute:

  2. Calculate the rate of tap P.

    Tap P fills 2000 litres in 10 minutes.

    Rate of P=Total capacityTime taken by P=2000 litres10 minutes\text{Rate of P} = \frac{\text{Total capacity}}{\text{Time taken by P}} = \frac{2000 \text{ litres}}{10 \text{ minutes}} Rate of P=200 litres/minute\text{Rate of P} = 200 \text{ litres/minute}

    Tap P fills 200 litres into the tank in one minute.

    200 litres\boxed{200 \text{ litres}}
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