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A) The sum of three consecutive integers is 42. Find the integers. b) Find the range of these integers.

Mathematics

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Answers

2 parts
a

13, 14, 15\text{13, 14, 15}

b
2

Step-by-step solution

5 steps

Part a· 3 steps

  1. Let the three consecutive integers be xx, x+1x+1, and x+2x+2.

    Their sum is 42.

    x+(x+1)+(x+2)=42x + (x+1) + (x+2) = 42
  2. Combine like terms and solve for xx.

    3x+3=423x + 3 = 42 3x=42−33x = 42 - 3 3x=393x = 39 x=393x = \frac{39}{3} x=13x = 13
  3. Find the three integers.

    The first integer is x=13x = 13.
    The second integer is x+1=13+1=14x+1 = 13+1 = 14.
    The third integer is x+2=13+2=15x+2 = 13+2 = 15.
    The three numbers are 13, 14, 15\boxed{\text{13, 14, 15}}.

Part b2

  1. Identify the largest and smallest numbers.

    Smallest number = 13
    Largest number = 15

  2. Calculate the range.

    Range = Largest number - Smallest number
    Range = 15−1315 - 13
    Range = 2\boxed{2}

    1. a) To construct a regular hexagon in a circle of radius 4cm:
    2. Draw a circle with a radius of 4cm using a compass. Mark the center point.
    3. Mark any point on the circumference of the circle. This will be the first vertex of the hexagon.
    4. Place the compass point on this first vertex and, keeping the compass opening at 4cm (the radius of the circle), draw an arc that intersects the circle at a second point.
    5. Move the compass point to this second intersection point and repeat the process, drawing another arc to find a third point on the circumference.
    6. Continue this process around the circle until you have marked six points on the circumference. The sixth point should coincide with the first point you marked.
    7. Using a ruler, connect these six points consecutively with straight lines. These lines form the sides of the regular hexagon.
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