This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Answer
1, 2, -12
Here are the solutions to the questions.
Step 1: Choose two positive integers. Let's choose 1 and 2.
Step 2: Find the third integer such that the sum is -9. Let the three integers be . We have and .
Step 3: Solve for . So, the three integers are 1, 2, and -12.
The final answer for 3.4 is (other combinations are possible).
Step 1: Define the initial amount of money. Let be the total amount of money Mr. Jacobs had in his wallet initially.
Step 2: Calculate the total fraction of money spent. He spent on sweets and on soft drinks. Total fraction spent . To add these fractions, find a common denominator, which is 6.
Step 3: Calculate the fraction of money remaining. The fraction of money remaining is .
Step 4: Use the remaining amount to find the initial money. We are told that R25 is remaining, which represents of the initial money.
Step 5: Solve for . Multiply both sides by 6:
The final answer for 3.5 is .
The pattern grows by adding a new row of squares at the top in each subsequent stage. The number of squares in the new row is equal to the stage number. The total number of squares in each stage is the sum of consecutive integers from 1 up to the stage number.
Step 1: Determine the number of squares in each stage. Stage 1: 1 square Stage 2: squares Stage 3: squares This is a sequence of triangular numbers, where the number of squares in stage is given by the formula .
Step 2: Calculate the number of squares for the 40th stage. Substitute into the formula:
The final answer for 4.1.2 is .
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Choose two positive integers. Let's choose 1 and 2.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.