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4 Find three integers of which the sum is -9. (Hint: Use two positive integers and one negative integer)

Mathematics

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Question 3.4

  1. Choose two positive integers.

    Let's choose 1 and 2.

  2. Find the third integer such that the sum is -9.

    Let the three integers be a,b,ca, b, c. We have a=1a=1 and b=2b=2.

    a+b+c=−9a + b + c = -9 1+2+c=−91 + 2 + c = -9 3+c=−93 + c = -9
  3. Solve for cc.

    c=−9−3c = -9 - 3 c=−12c = -12

    So, the three integers are 1, 2, and -12.

    The final answer for 3.4 is 1,2,−12\boxed{1, 2, -12} (other combinations are possible).

    Question 3.5

  4. Define the initial amount of money.

    Let MM be the total amount of money Mr. Jacobs had in his wallet initially.

  5. Calculate the total fraction of money spent.

    He spent 12\frac{1}{2} on sweets and 13\frac{1}{3} on soft drinks.
    Total fraction spent =12+13= \frac{1}{2} + \frac{1}{3}.
    To add these fractions, find a common denominator, which is 6.

    12+13=36+26=56\frac{1}{2} + \frac{1}{3} = \frac{3}{6} + \frac{2}{6} = \frac{5}{6}
  6. Calculate the fraction of money remaining.

    The fraction of money remaining is 1−total fraction spent1 - \text{total fraction spent}.

    1−56=66−56=161 - \frac{5}{6} = \frac{6}{6} - \frac{5}{6} = \frac{1}{6}
  7. Use the remaining amount to find the initial money.

    We are told that R25 is remaining, which represents 16\frac{1}{6} of the initial money.

    16M=25\frac{1}{6} M = 25
  8. Solve for MM.

    Multiply both sides by 6:

    M=25×6M = 25 \times 6 M=150M = 150

    The final answer for 3.5 is R150\boxed{\text{R}150}.

    Question 4.1.1

    The pattern grows by adding a new row of squares at the top in each subsequent stage. The number of squares in the new row is equal to the stage number. The total number of squares in each stage is the sum of consecutive integers from 1 up to the stage number.

    Question 4.1.2

  9. Determine the number of squares in each stage.

    Stage 1: 1 square
    Stage 2: 1+2=31 + 2 = 3 squares
    Stage 3: 1+2+3=61 + 2 + 3 = 6 squares
    This is a sequence of triangular numbers, where the number of squares in stage nn is given by the formula Tn=n(n+1)2T_n = \frac{n(n+1)}{2}.

  10. Calculate the number of squares for the 40th stage.

    Substitute n=40n = 40 into the formula:

    T40=40(40+1)2T_{40} = \frac{40(40+1)}{2} T40=40×412T_{40} = \frac{40 \times 41}{2} T40=20×41T_{40} = 20 \times 41 T40=820T_{40} = 820

    The final answer for 4.1.2 is 820 squares\boxed{820 \text{ squares}}.

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