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A transporter wishes to transfer 1000 bags of sugar. An FTR lorry can carry 80 bags and a canter lorry can carry 20 bags. The canter has to make at most twice as many trips as the FTR, and the total n

Mathematics

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Step-by-step solution

6 steps

Part a· 3 steps

  1. Define variables.

    Let xx be the number of trips made by the FTR lorry.
    Let yy be the number of trips made by the canter lorry.

  2. Formulate inequalities based on the problem statement.

    • "The canter has to make at most twice as many trips as the FTR makes." y≤2xy \le 2x
    • "The total number of trips made by both lorries must be less than 30." x+y<30x + y < 30
    • "A transporter wishes to transfer 1000 bags of sugar." FTR capacity is 80 bags, canter capacity is 20 bags. The total bags transferred must be at least 1000. 80x+20y≥100080x + 20y \ge 1000 This simplifies to: 4x+y≥504x + y \ge 50
    • "The canter has to make more than 10 trips." y>10y > 10
    • Implicitly, the number of trips cannot be negative. Since y>10y > 10, y≥0y \ge 0 is already satisfied. We also need: x≥0x \ge 0
  3. List all the possible inequalities.

    The inequalities are:

    1. y≤2xy \le 2x
    2. x+y<30x + y < 30
    3. 4x+y≥504x + y \ge 50
    4. y>10y > 10
    5. x≥0x \ge 0

Part b· 3 steps

To represent the information on a grid:

  1. Draw and label the axes.

    Draw a horizontal x-axis (for FTR trips) and a vertical y-axis (for canter trips). Since x≥0x \ge 0 and y>10y > 10, focus on the first quadrant, with the y-axis starting above 10.

  2. Draw the boundary lines for each inequality.

    • For y≤2xy \le 2x, draw the line y=2xy = 2x. This line should be solid.
    • For x+y<30x + y < 30, draw the line x+y=30x + y = 30. This line should be dashed.
    • For 4x+y≥504x + y \ge 50, draw the line 4x+y=504x + y = 50. This line should be solid.
    • For y>10y > 10, draw the line y=10y = 10. This line should be dashed.
    • For x≥0x \ge 0, this is the y-axis. This line should be solid.
  3. Shade the feasible region.

    Determine the region that satisfies each inequality:

    • For y≤2xy \le 2x, shade the region below or on the line y=2xy = 2x.
    • For x+y<30x + y < 30, shade the region below the line x+y=30x + y = 30.
    • For 4x+y≥504x + y \ge 50, shade the region above or on the line 4x+y=504x + y = 50.
    • For y>10y > 10, shade the region above the line y=10y = 10.
    • For x≥0x \ge 0, shade the region to the right or on the line x=0x = 0.

    The feasible region is the area where all shaded regions overlap. This region represents all possible combinations of trips (x,y)(x,y) that satisfy all the given conditions.

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