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A tree breaks due to storm. The broken part makes an angle of 30 degrees with the ground and the distance from the foot of the tree to the point where the top touches the ground is 8 m. Find the total

Mathematics

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Answer

83 m8\sqrt{3} \text{ m}

Step-by-step solution

4 steps
  1. Identify the components of the right-angled triangle formed.

    Let hh be the height of the standing part of the tree and LL be the length of the broken part that touches the ground. The total height of the tree is H=h+LH = h + L.
    The distance from the foot of the tree to where the top touches the ground is 8 m8 \text{ m}.
    The angle made by the broken part with the ground is 30∘30^\circ.

  2. Calculate the height of the standing part of the tree (hh).

    We use the tangent function, which relates the opposite side (hh) to the adjacent side (8 m8 \text{ m}).

    tan⁡(θ)=oppositeadjacent\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} tan⁡(30∘)=h8\tan(30^\circ) = \frac{h}{8}

    We know that tan⁡(30∘)=13\tan(30^\circ) = \frac{1}{\sqrt{3}}.

    13=h8\frac{1}{\sqrt{3}} = \frac{h}{8} h=83 mh = \frac{8}{\sqrt{3}} \text{ m}
  3. Calculate the length of the broken part of the tree (LL).

    We use the cosine function, which relates the adjacent side (8 m8 \text{ m}) to the hypotenuse (LL).

    cos⁡(θ)=adjacenthypotenuse\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}} cos⁡(30∘)=8L\cos(30^\circ) = \frac{8}{L}

    We know that cos⁡(30∘)=32\cos(30^\circ) = \frac{\sqrt{3}}{2}.

    32=8L\frac{\sqrt{3}}{2} = \frac{8}{L} L=8×23L = \frac{8 \times 2}{\sqrt{3}} L=163 mL = \frac{16}{\sqrt{3}} \text{ m}
  4. Calculate the total height of the tree (HH).

    The total height is the sum of the standing part and the broken part.

    H=h+LH = h + L H=83+163H = \frac{8}{\sqrt{3}} + \frac{16}{\sqrt{3}} H=8+163H = \frac{8 + 16}{\sqrt{3}} H=243H = \frac{24}{\sqrt{3}}

    To rationalize the denominator, multiply the numerator and denominator by 3\sqrt{3}:

    H=243×33H = \frac{24}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} H=2433H = \frac{24\sqrt{3}}{3} H=83 mH = 8\sqrt{3} \text{ m}

    The height of the tree is 83 m8\sqrt{3} \text{ m}.

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