A wall has a total length of 5.48 meters. It has two garage doors, each 2.44 meters wide and 2.1 meters high. There are also two side wall sections, each 0.15 meters wide. Calculate the area of the wa

From the diagram:
The length (height) of one garage door is $2100 \text{ mm}$.
The width of one garage door is $2440 \text{ mm}$.
To convert millimeters to meters, we divide by 1000.

$$\text{Length} = \frac{2100 \text{ mm}}{1000 \text{ mm/m}} = 2.100 \text{ m}$$ $$\text{Width} = \frac{2440 \text{ mm}}{1000 \text{ mm/m}} = 2.440 \text{ m}$$

The length of one garage door is $\boxed{\text{2.100 m}}$ and the width is $\boxed{\text{2.440 m}}$.

The total length of the wall is given as $5480 \text{ mm}$.
The diagram shows two side wall sections, each $150 \text{ mm}$ wide.
The diagram shows two garage doors, each $2440 \text{ mm}$ wide.
The total length of the wall is the sum of the two side wall sections, the two garage door widths, and the length A between the doors.

$$5480 \text{ mm} = (2 \times 150 \text{ mm}) + (2 \times 2440 \text{ mm}) + A$$ $$5480 \text{ mm} = 300 \text{ mm} + 4880 \text{ mm} + A$$ $$5480 \text{ mm} = 5180 \text{ mm} + A$$ $$A = 5480 \text{ mm} - 5180 \text{ mm}$$ $$A = 300 \text{ mm}$$

The length of A is $\boxed{\text{300 mm}}$.

The area of one garage door is its length (height) multiplied by its width.
Length of one garage door = $2100 \text{ mm}$
Width of one garage door = $2440 \text{ mm}$

$$\text{Area of one garage door} = 2100 \text{ mm} \times 2440 \text{ mm} = 5124000 \text{ mm}^2$$

The total area of the two garage doors is twice the area of one garage door.

$$\text{Total area of two garage doors} = 2 \times 5124000 \text{ mm}^2 = 10248000 \text{ mm}^2$$

The total area of the two garage doors is $\boxed{\text{10248000 mm}^2}$.

Give your answer in m².
First, calculate B.

$$B = 1.5 \times A$$

From Step 2, $