This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
Step 1: Calculate the total area of the four walls. The bedroom has a length of 6 m, a width of 4 m, and a height of 2.8 m. The total area of the four walls is given by the perimeter multiplied by the height. Perimeter = 2 × (length + width) Perimeter = 2 × (6 m + 4 m) = 2 × 10 m = 20 m Area of walls = Perimeter × height Area of walls = 20 m × 2.8 m = 56 m^2 Step 2: Calculate the area of the window. The window has a width of 1.2 m and a height of 1.5 m. Area of window = width × height Area of window = 1.2 m × 1.5 m = 1.8 m^2 Step 3: Calculate the area of the door. The door has a width of 0.9 m and a height of 2.1 m. Area of door = width × height Area of door = 0.9 m × 2.1 m = 1.89 m^2 Step 4: Calculate the total area to be painted. The area to be painted is the total wall area minus the areas of the window and the door. Area to be painted = Area of walls - Area of window - Area of door Area to be painted = 56 m^2 - 1.8 m^2 - 1.89 m^2 Area to be painted = 56 m^2 - 3.69 m^2 = 52.31 m^2 Step 5: Calculate the total litres of paint needed. 1 litre of paint covers 9 m^2. Litres needed = Area to be paintedCoverage per litre Litres needed = 52.31 m^29 m^2/litre ≈ 5.8122 litres Step 6: Calculate the number of 5-litre cans to buy. Paint is sold in 5-litre cans only. Since Thabiso cannot buy a fraction of a can, he must round up to ensure he has enough paint. Number of cans = Litres neededLitres per can Number of cans = 5.8122 litres5 litres/can ≈ 1.1624 cans Rounding up to the nearest whole can: Number of cans = 1.1624 = 2 cans Thabiso needs to buy 2 cans of paint. That's 2 down. 3 left today — send the next one.