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You are planning to renovate your bedroom. Your builder told you that you will need the following items: paint, tiles, ceiling board, cornice, tile cement, tile drought, bend rings, ceiling nail and cornice adhesive. You decided to get a quote from a hardware store. Measure the dimensions of your bedroom's walls, windows, and door, in metres (Length, Breadth, and Height). Calculate the surface area of the walls of your bedroom. Determine the amount of paint, in liters, needed for painting your bedroom, excluding the first coat. Calculate the area of the floor that needs to be tiled. Write down the dimensions of the tile and determine the number of tiles in 1 box. Hence, determine the total number of tile boxes needed if an additional 10% of the tiles must be added. Explain why it is important to buy extra tiles. Attach pictures of the product you plan to use to renovate your bedroom and complete the table in Annexure B, listing the items, quantities, and amounts.

Mathematics

ScanSolve AI Answer

Step-by-step solution

6 steps
  1. Measure dimensions (assumed values for calculation

    length l=5l=5 m, breadth b=4b=4 m, height h=2.5h=2.5 m). Doors/windows approximated using NOTE.

    Floor area = length ×\times breadth

    5×4=20 m25 \times 4 = 20~\mathrm{m}^2

    10% of floor area to deduct (for doors/windows/furniture)

    0.1×20=2 m20.1 \times 20 = 2~\mathrm{m}^2
  2. Surface area of length walls (Areas 1 and 3)

    Area of one = length ×\times height

    5×2.5=12.5 m25 \times 2.5 = 12.5~\mathrm{m}^2

    Total for two = 2×2 \times area of one

    2×12.5=25 m22 \times 12.5 = 25~\mathrm{m}^2

    Surface area of breadth walls (Areas 2 and 4)
    Area of one = breadth ×\times height

    4×2.5=10 m24 \times 2.5 = 10~\mathrm{m}^2

    Total for two = 2×2 \times area of one

    2×10=20 m22 \times 10 = 20~\mathrm{m}^2
  3. Total surface area of all walls

    Total = length walls + breadth walls

    25+20=45 m225 + 20 = 45~\mathrm{m}^2
  4. Area that needs to be painted

    Paint area = total walls −- 10% floor area

    45−2=43 m245 - 2 = 43~\mathrm{m}^2
  5. Number of tins needed (assume 12 m² per tin coverage, typical for one coat)

    Tins without extra = paint area ÷\div coverage per tin

    43÷12≈3.5843 \div 12 \approx 3.58

    Buy 4 tins (entire tins).

  6. With additional 10% (for waste/extra coats)

    Area with extra = paint area ×1.1\times 1.1

    43×1.1=47.3 m243 \times 1.1 = 47.3~\mathrm{m}^2

    Tins with extra = area with extra ÷\div coverage per tin

    47.3÷12≈3.9447.3 \div 12 \approx 3.94

    Buy 4 tins (entire tins).

    DescriptionArea (m²)
    Length walls (2)25
    Breadth walls (2)20
    Total walls45
    Deduct 10% floor2
    Paint area43
    With 10% extra47.3
    Tins (12 m²/tin)4

    You buy entire tins because paint is sold in whole tins only; cannot buy partial tins. Attach photo of tins at store.

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