You are planning to renovate your bedroom. Your builder told you that you will need the following items: paint, tiles, ceiling board, cornice, tile cement, tile drought, bend rings, ceiling nail and cornice adhesive. You decided to get a quote from a hardware store. Measure the dimensions of your bedroom's walls, windows, and door, in metres (Length, Breadth, and Height). Calculate the surface area of the walls of your bedroom. Determine the amount of paint, in liters, needed for painting your bedroom, excluding the first coat. Calculate the area of the floor that needs to be tiled. Write down the dimensions of the tile and determine the number of tiles in 1 box. Hence, determine the total number of tile boxes needed if an additional 10% of the tiles must be added. Explain why it is important to buy extra tiles. Attach pictures of the product you plan to use to renovate your bedroom and complete the table in Annexure B, listing the items, quantities, and amounts.

Question 1

Answer · 2026-03-15T19:47:12.245Z

Step 1: Measure dimensions (assumed values for calculation: length l=5 m, breadth b=4 m, height h=2.5 m). Doors/windows approximated using NOTE. Floor area = length × breadth 5 × 4 = 20~m^2 10% of floor area to deduct (for doors/windows/furniture) 0.1 × 20 = 2~m^2 Step 2: Surface area of length walls (Areas 1 and 3) Area of one = length × height 5 × 2.5 = 12.5~m^2 Total for two = 2 × area of one 2 × 12.5 = 25~m^2 Surface area of breadth walls (Areas 2 and 4) Area of one = breadth × height 4 × 2.5 = 10~m^2 Total for two = 2 × area of one 2 × 10 = 20~m^2 Step 3: Total surface area of all walls Total = length walls + breadth walls 25 + 20 = 45~m^2 Step 4: Area that needs to be painted Paint area = total walls - 10% floor area 45 - 2 = 43~m^2 Step 5: Number of tins needed (assume 12 m² per tin coverage, typical for one coat) Tins without extra = paint area ÷ coverage per tin 43 ÷ 12 ≈ 3.58 Buy 4 tins (entire tins). Step 6: With additional 10% (for waste/extra coats) Area with extra = paint area × 1.1 43 × 1.1 = 47.3~m^2 Tins with extra = area with extra ÷ coverage per tin 47.3 ÷ 12 ≈ 3.94 Buy 4 tins (entire tins). | Description | Area (m²) | |-------------------|-----------| | Length walls (2) | 25 | | Breadth walls (2) | 20 | | Total walls | 45 | | Deduct 10% floor | 2 | | Paint area | 43 | | With 10% extra | 47.3 | | Tins (12 m²/tin) | 4 | You buy entire tins because paint is sold in whole tins only; cannot buy partial tins. Attach photo of tins at store.

Question 2

Step 1: Measure dimensions (assumed values for calculation: length l=5 m, breadth b=4 m, height h=2.5 m). Doors/windows approximated using NOTE. Floor area = length × breadth 5 × 4 = 20~m^2 10% of floor area to deduct (for doors/windows/furniture) 0.1 × 20 = 2~m^2 Step 2: Surface area of length walls (Areas 1 and 3) Area of one = length × height 5 × 2.5 = 12.5~m^2 Total for two = 2 × area of one 2 × 12.5 = 25~m^2 Surface area of breadth walls (Areas 2 and 4) Area of one = breadth × height 4 × 2.5 = 10~m^2 Total for two = 2 × area of one 2 × 10 = 20~m^2 Step 3: Total surface area of all walls Total = length walls + breadth walls 25 + 20 = 45~m^2 Step 4: Area that needs to be painted Paint area = total walls - 10% floor area 45 - 2 = 43~m^2 Step 5: Number of tins needed (assume 12 m² per tin coverage, typical for one coat) Tins without extra = paint area ÷ coverage per tin 43 ÷ 12 ≈ 3.58 Buy 4 tins (entire tins). Step 6: With additional 10% (for waste/extra coats) Area with extra = paint area × 1.1 43 × 1.1 = 47.3~m^2 Tins with extra = area with extra ÷ coverage per tin 47.3 ÷ 12 ≈ 3.94 Buy 4 tins (entire tins). | Description | Area (m²) | |-------------------|-----------| | Length walls (2) | 25 | | Breadth walls (2) | 20 | | Total walls | 45 | | Deduct 10% floor | 2 | | Paint area | 43 | | With 10% extra | 47.3 | | Tins (12 m²/tin) | 4 | You buy entire tins because paint is sold in whole tins only; cannot buy partial tins. Attach photo of tins at store.

Need help with your own homework?

More Mathematics Questions