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ABCD is a rectangle. M is the midpoint of CD. Find the following in terms of u and v.

Mathematics

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Answers

2 parts
2

−u+v-\mathbf{u} + \mathbf{v}

3

−u+w-\mathbf{u} + \mathbf{w}

Step-by-step solution

4 steps

let's continue with Questions 2 and 3.

For Questions 2 and 3, refer to the new diagram where:
AB⃗=u\vec{AB} = \mathbf{u}
AD⃗=v\vec{AD} = \mathbf{v}
AC⃗=w\vec{AC} = \mathbf{w}

Part 2· 2 steps

Express BD⃗\vec{BD} in terms of u\mathbf{u}, v\mathbf{v}, and w\mathbf{w}.

  1. Use the triangle rule for vector addition.

    To go from B to D, we can follow the path from B to A, then from A to D.

    BD⃗=BA⃗+AD⃗\vec{BD} = \vec{BA} + \vec{AD}
  2. Substitute the given vectors.

    We know BA⃗=−AB⃗\vec{BA} = -\vec{AB}, so BA⃗=−u\vec{BA} = -\mathbf{u}.
    We are given AD⃗=v\vec{AD} = \mathbf{v}.

    BD⃗=−u+v\vec{BD} = -\mathbf{u} + \mathbf{v}

    The expression for BD⃗\vec{BD} is −u+v\boxed{-\mathbf{u} + \mathbf{v}}.

Part 3

−u+w-\mathbf{u} + \mathbf{w}

Express BC⃗\vec{BC} in terms of u\mathbf{u}, v\mathbf{v}, and w\mathbf{w}.

  1. Use the triangle rule for vector addition.

    To go from B to C, we can follow the path from B to A, then from A to C.

    BC⃗=BA⃗+AC⃗\vec{BC} = \vec{BA} + \vec{AC}
  2. Substitute the given vectors.

    We know BA⃗=−AB⃗\vec{BA} = -\vec{AB}, so BA⃗=−u\vec{BA} = -\mathbf{u}.
    We are given AC⃗=w\vec{AC} = \mathbf{w}.

    BC⃗=−u+w\vec{BC} = -\mathbf{u} + \mathbf{w}

    The expression for BC⃗\vec{BC} is −u+w\boxed{-\mathbf{u} + \mathbf{w}}.

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