This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Step 1: Acceleration is zero when velocity is constant. In an x-t graph, constant velocity appears as a straight line (non-zero slope). Observe the graphs: Graph (A) is a straight line (constant slope), so acceleration is zero throughout. Graphs (B), (C), (D) are curved or piecewise, indicating changing velocity. Answer for Q12: (A) Step 1: Maximum velocity from v-t graph is the highest v value (peak ordinate). Step 2: Maximum displacement is the maximum area under v-t curve up to that point ( v \, dt). Step 3: Maximum acceleration is the maximum slope of v-t graph ( ( v)/( t)). Step 4: Average displacement is total area under curve divided by time interval ((1)/(T) _0^T v \, dt). (Specific values require graph scales; read from given v-t graphs for A, B, C, D.) The area under v-t graph represents displacement ( v \, dt = x), not velocity or acceleration. Velocity = ordinate value. Acceleration = slope. neither (A) nor (B); it is displacement