According to the grade 11-12 Zambian syllabus answer this math question for me

We can factor the numerator: $x^2 + 3x - 4 = (x+4)(x-1)$.
So, the expression becomes $\frac{(x+4)(x-1)}{x-1}$.
For $x \neq 1$, this simplifies to $x+4$.

We need to find the derivative of $x+4$ with respect to $x$.

The derivative of $x$ (which is $x^1$) is $1 \cdot x^{1-1} = 1 \cdot x^0 = 1$.
The derivative of a constant (4) is 0.

The derivative of the given expression is 1.