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Add the following vectors: a) X + Y where X = [10, 4] and Y = [-4, 8]; b) [7, 2] + [5, -1]. Find AB as a column vector if OA = [2, 4] and OB = [3, 2].

Mathematics

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Answers

2 parts
b

(612)\begin{pmatrix} 6 \\ 12 \end{pmatrix}

c

(121)\begin{pmatrix} 12 \\ 1 \end{pmatrix}

(1−2)\begin{pmatrix} 1 \\ -2 \end{pmatrix}

Step-by-step solution

7 steps

Part b· 2 steps

  1. Add the corresponding components of the vectors.

    X+Y=(104)+(−48)=(10+(−4)4+8)X + Y = \begin{pmatrix} 10 \\ 4 \end{pmatrix} + \begin{pmatrix} -4 \\ 8 \end{pmatrix} = \begin{pmatrix} 10+(-4) \\ 4+8 \end{pmatrix}
  2. Simplify the components.

    X+Y=(612)X + Y = \begin{pmatrix} 6 \\ 12 \end{pmatrix}

    The sum is (612)\boxed{\begin{pmatrix} 6 \\ 12 \end{pmatrix}}.

Part c

(121)\begin{pmatrix} 12 \\ 1 \end{pmatrix}

  1. Add the corresponding components of the vectors.

    (72)+(5−1)=(7+52+(−1))\begin{pmatrix} 7 \\ 2 \end{pmatrix} + \begin{pmatrix} 5 \\ -1 \end{pmatrix} = \begin{pmatrix} 7+5 \\ 2+(-1) \end{pmatrix}
  2. Simplify the components.

    (72)+(5−1)=(121)\begin{pmatrix} 7 \\ 2 \end{pmatrix} + \begin{pmatrix} 5 \\ -1 \end{pmatrix} = \begin{pmatrix} 12 \\ 1 \end{pmatrix}

    The sum is (121)\boxed{\begin{pmatrix} 12 \\ 1 \end{pmatrix}}.

    2. Find AB as a column vector
    Given OA⃗=(24)\vec{OA} = \begin{pmatrix} 2 \\ 4 \end{pmatrix} and OB⃗=(32)\vec{OB} = \begin{pmatrix} 3 \\ 2 \end{pmatrix}.

  3. Use the formula for finding a vector between two points

    AB⃗=OB⃗−OA⃗\vec{AB} = \vec{OB} - \vec{OA}.

    AB⃗=(32)−(24)\vec{AB} = \begin{pmatrix} 3 \\ 2 \end{pmatrix} - \begin{pmatrix} 2 \\ 4 \end{pmatrix}
  4. Subtract the corresponding components.

    AB⃗=(3−22−4)\vec{AB} = \begin{pmatrix} 3-2 \\ 2-4 \end{pmatrix}
  5. Simplify the components.

    AB⃗=(1−2)\vec{AB} = \begin{pmatrix} 1 \\ -2 \end{pmatrix}

    The column vector AB⃗\vec{AB} is (1−2)\boxed{\begin{pmatrix} 1 \\ -2 \end{pmatrix}}.

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