All about binomial theorem

Mathematics

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(a+b)n=∑k=0n(nk)an−kbk(a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k

The binomial theorem provides a formula for expanding expressions of the form (a+b)n(a+b)^n for any positive integer nn. It simplifies the process of multiplying a binomial by itself many times.

The general formula for the binomial theorem is:

(a+b)n=∑k=0n(nk)an−kbk(a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k

Where:

  • nn is a non-negative integer.
  • kk is an integer from 0 to nn.
  • (nk)\binom{n}{k} is the binomial coefficient, calculated as n!k!(n−k)!\frac{n!}{k!(n-k)!}.

For example, let's expand (x+y)3(x+y)^3:

(x+y)3=(30)x3−0y0+(31)x3−1y1+(32)x3−2y2+(33)x3−3y3=1⋅x3⋅1+3⋅x2⋅y+3⋅x1⋅y2+1⋅1⋅y3=x3+3x2y+3xy2+y3\begin{align*} (x+y)^3 &= \binom{3}{0} x^{3-0} y^0 + \binom{3}{1} x^{3-1} y^1 + \binom{3}{2} x^{3-2} y^2 + \binom{3}{3} x^{3-3} y^3 \\ &= 1 \cdot x^3 \cdot 1 + 3 \cdot x^2 \cdot y + 3 \cdot x^1 \cdot y^2 + 1 \cdot 1 \cdot y^3 \\ &= x^3 + 3x^2y + 3xy^2 + y^3 \end{align*}
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