Determine A and A from A = (4)/(3).

Since $A$ is an acute angle, we can use a right-angled triangle.
Opposite side = 4, Adjacent side = 3.
Hypotenuse = $\sqrt{4^2 + 3^2} = \sqrt{16 + 9} = \sqrt{25} = 5$.
Therefore, $\sin A = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{4}{5}$ and $\cos A = \frac{\text{Adjacent}}{\text{Hypotenuse}} = \frac{3}{5}$.

Since $B$ is an acute angle, we can use the identity $\sin^2 B + \cos^2 B = 1$.

Since $B$ is acute, $\sin B$ is positive.

Substitute the values found:

Comparing this with the given options, the correct option is (b).

The exact value of $\sin(A + B)$ is $\boxed{\text{(b) } \frac{56}{65}}$.