Calculate the angle beta in triangle 'b'.

In the right-angled triangle 'b', the side opposite to angle $\beta$ is 9, and the hypotenuse is 20. We use the sine function.

$$\sin(\beta) = \frac{\text{opposite}}{\text{hypotenuse}}$$ $$\sin(\beta) = \frac{9}{20}$$ $$\sin(\beta) = 0.45$$

To find $\beta$, we take the inverse sine:

$$\beta = \arcsin(0.45)$$ $$\beta \approx 26.7436^\circ$$

Rounding to the nearest 0.1 degree:

$$\beta \approx \boxed{26.7^\circ}$$

In the right-angled triangle 'd', the side opposite to angle $\delta$ is 8, and the side adjacent to angle $\delta$ is 6. We use the tangent function.

$$\tan(\delta) = \frac{\text{opposite}}{\text{adjacent}}$$ $$\tan(\delta) = \frac{8}{6}$$ $$\tan(\delta) = \frac{4}{3}$$

To find $\delta$, we take the inverse tangent:

$$\delta = \arctan\left(\frac{4}{3}\right)$$ $$\delta \approx 53.1301^\circ$$

Rounding to the nearest 0.1 degree:

$$\delta \approx \boxed{53.1^\circ}$$