Step 1: Complete Question 1
...no effect on litmus paper. This is because ammonia does not ionize in methylbenzene to produce hydroxide ions (OH−), which are responsible for basic properties.
Step 2: Answer Question 2
a) Calculate the number of moles of H2SO4.
Volume of H2SO4=25.0cm3=0.0250dm3.
Concentration of H2SO4=0.100moldm−3.
MolesofH2SO4=Concentration×Volume
MolesofH2SO4=0.100moldm−3×0.0250dm3
MolesofH2SO4=0.00250 mol
b) Calculate the number of moles of NaOH that reacted.
The balanced chemical equation is:
H2SO4(aq)+2NaOH(aq)→Na2SO4(aq)+2H2O(l)
From the equation, 1moleofH2SO4 reacts with 2molesofNaOH.
MolesofNaOH=2×MolesofH2SO4
MolesofNaOH=2×0.00250mol
MolesofNaOH=0.00500 mol
c) Calculate the concentration of the NaOH solution.
Volume of NaOH=20.0cm3=0.0200dm3.
ConcentrationofNaOH=VolumeofNaOHMolesofNaOH
ConcentrationofNaOH=0.0200dm30.00500mol
Concentration of NaOH = \text{0.250 mol dm^{-3}}
Step 3: Answer Question 3
a) The type of reaction that occurs when H2SO4 reacts with NaOH is a neutralization reaction.
b) A common indicator used in this titration (strong acid-strong base) is phenolphthalein.
Step 4: Answer Question 4
a) If phenolphthalein is used, the colour of the indicator in the conical flask (containing H2SO4) at the start of the titration is colorless.
b) If phenolphthalein is used, the colour of the indicator in the conical flask at the end-point of the titration is pink.
Step 5: Answer Question 5
a) Apparatus A is a burette.
b) Apparatus B is a pipette.
c) Apparatus C is a conical flask (or Erlenmeyer flask).
d) Apparatus D is a retort stand (with a clamp).
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