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When a certain number is increased by five, the result is six times the same number decreased by ten. What is the number?

Mathematics

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2. When a certain number is increased by five, the result is six times the same number decreased by ten. What is the number?

  1. Let the number be xx.

    Translate the problem into an equation.
    "A certain number is increased by five" can be written as x+5x + 5.
    "Six times the same number decreased by ten" can be written as 6(x−10)6(x - 10).
    The problem states that these two expressions are equal.

    x+5=6(x−10)x + 5 = 6(x - 10)
  2. Distribute the 6 on the right side of the equation.

    x+5=6x−60x + 5 = 6x - 60
  3. Gather the xx terms on one side and the constant terms on the other side.

    Subtract xx from both sides:

    5=5x−605 = 5x - 60

    Add 60 to both sides:

    5+60=5x5 + 60 = 5x 65=5x65 = 5x
  4. Solve for xx by dividing both sides by 5.

    655=x\frac{65}{5} = x x=13x = 13

    The number is 13\boxed{\text{13}}.

    3. If 35\frac{3}{5} of a numbers is 4 more than 12\frac{1}{2} the number, what is the number? Ans 40

  5. Let the number be xx.

    Translate the problem into an equation.
    "35\frac{3}{5} of a number" can be written as 35x\frac{3}{5}x.
    "4 more than 12\frac{1}{2} the number" can be written as 12x+4\frac{1}{2}x + 4.
    The problem states that these two expressions are equal.

    35x=12x+4\frac{3}{5}x = \frac{1}{2}x + 4
  6. To eliminate the fractions, multiply the entire equation by the least common multiple (LCM) of the denominators (5 and 2), which is 10.

    10⋅(35x)=10⋅(12x+4)10 \cdot \left(\frac{3}{5}x\right) = 10 \cdot \left(\frac{1}{2}x + 4\right) 6x=5x+406x = 5x + 40
  7. Gather the xx terms on one side.

    Subtract 5x5x from both sides:

    6x−5x=406x - 5x = 40 x=40x = 40

    The number is 40\boxed{\text{40}}. This matches the given answer.

    4. I am thinking of a certain number. If I multiply by 6, add -18 to the product and multiply by one - third of the result, I get -2. What number am I thinking of?

  8. Let the number be xx.

    Translate the problem into an equation.
    "Multiply by 6": 6x6x
    "Add -18 to the product": 6x−186x - 18
    "Multiply by one-third of the result": 13(6x−18)\frac{1}{3}(6x - 18)
    "I get -2": means the expression equals -2.

    13(6x−18)=−2\frac{1}{3}(6x - 18) = -2
  9. Distribute 13\frac{1}{3} into the parenthesis.

    13(6x)−13(18)=−2\frac{1}{3}(6x) - \frac{1}{3}(18) = -2 2x−6=−22x - 6 = -2
  10. Isolate the term with xx.

    Add 6 to both sides of the equation:

    2x=−2+62x = -2 + 6 2x=42x = 4
  11. Solve for xx by dividing both sides by 2.

    x=42x = \frac{4}{2} x=2x = 2

    The number is 2\boxed{\text{2}}.

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