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A. Write an equation and solve it. 1. Six times a certain number decreased by two is four times the same number increased by twelve. Find the number.

Mathematics

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Here's the solution for the next problem:

1. Six times a certain number decreased by two is four times the same number increased by twelve. Find the number.

  1. Let the certain number be xx.

    Translate the problem into an equation.
    "Six times a certain number decreased by two" can be written as 6x−26x - 2.
    "Four times the same number increased by twelve" can be written as 4(x+12)4(x + 12).
    The problem states that these two expressions are equal.

    6x−2=4(x+12)6x - 2 = 4(x + 12)
  2. Distribute the 4 on the right side of the equation.

    6x−2=4x+486x - 2 = 4x + 48
  3. Gather the xx terms on one side and the constant terms on the other side.

    Subtract 4x4x from both sides:

    6x−4x−2=486x - 4x - 2 = 48 2x−2=482x - 2 = 48

    Add 2 to both sides:

    2x=48+22x = 48 + 2 2x=502x = 50
  4. Solve for xx by dividing both sides by 2.

    x=502x = \frac{50}{2} x=25x = 25

    The number is 25\boxed{\text{25}}.

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