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Calculate the area of a trapezium with parallel sides 5.54 cm and 7.64 cm, and a height of 3.9 cm. Round to 2 decimal places.

May 26, 2026Mathematics

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Answer

\text{25.70 cm}^2

3 steps

Here's the solution for Q3.

Identify the dimensions of the trapezium.
The lengths of the parallel sides are $a = 5.54 \text{ cm}$ and $b = 7.64 \text{ cm}$ .
The perpendicular height is $h = 3.9 \text{ cm}$ .
Apply the formula for the area of a trapezium.
The formula for the area of a trapezium is $A = \frac{1}{2}(a+b)h$ .
$A = \frac{1}{2}(5.54 \text{ cm} + 7.64 \text{ cm}) \times 3.9 \text{ cm}$ $A = \frac{1}{2}(13.18 \text{ cm}) \times 3.9 \text{ cm}$ $A = 6.59 \text{ cm} \times 3.9 \text{ cm}$ $A = 25.701 \text{ cm}^2$
Round the area to 2 decimal places.
$A \approx 25.70 \text{ cm}^2$
The area of the trapezium is $\text{25.70 cm}^2$ .