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Determine the area of ACEG in the simplest possible form. Expand the product of (x+6)(x+4) and find the product of (x+8)(x+5)

Mathematics

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1.3 Determine the area of ACEG in the simplest possible form:

  1. Identify the four smaller areas that make up the total area of ACEG.

    Area of ACEG = Area of ABJH + Area of BCDJ + Area of HJFG + Area of DEFJ.

  2. Substitute the areas calculated in question 1.1.

    Area of ABJH =x2= x^2
    Area of BCDJ =6x= 6x
    Area of HJFG =4x= 4x
    Area of DEFJ =24= 24

  3. Sum these areas and simplify by combining like terms.

    Area of ACEG=x2+6x+4x+24\text{Area of ACEG} = x^2 + 6x + 4x + 24 Area of ACEG=x2+(6x+4x)+24\text{Area of ACEG} = x^2 + (6x + 4x) + 24 Area of ACEG=x2+10x+24 Units2\text{Area of ACEG} = \boxed{x^2 + 10x + 24 \text{ Units}^2}

    1.4 Using your answer in 1.2 and 1.3 find the area of ACEG in the form ax2+bx+c=ax^2 + bx + c =

  4. Use the lengths of the sides of the large rectangle ACEG from question 1.2.

    AC=x+6AC = x+6
    AG=x+4AG = x+4

  5. Multiply the lengths to find the area of ACEG.

    Area of ACEG=AC×AG=(x+6)(x+4)\text{Area of ACEG} = AC \times AG = (x+6)(x+4)
  6. Expand the product using the FOIL method (First, Outer, Inner, Last).

    (x+6)(x+4)=x⋅x+x⋅4+6⋅x+6⋅4(x+6)(x+4) = x \cdot x + x \cdot 4 + 6 \cdot x + 6 \cdot 4 =x2+4x+6x+24= x^2 + 4x + 6x + 24 =x2+10x+24= \boxed{x^2 + 10x + 24}

    1.5 (x+6)(x+4)=(x+6)(x+4)=

  7. Expand the product.

    (x+6)(x+4)=x2+4x+6x+24(x+6)(x+4) = x^2 + 4x + 6x + 24
  8. Combine like terms.

    =x2+10x+24= \boxed{x^2 + 10x + 24}

    2.1 Use the method you discovered in question 1 to determine the product of (x+8)(x+5)(x+8)(x+5)

    2.1.1 Area of KLQR =

  9. Identify the dimensions of rectangle KLQR.

    Length KL=xKL = x, Width KQ=xKQ = x.

  10. Calculate the area.

    Area of KLQR =KL×KQ=x×x=x2= KL \times KQ = x \times x = \boxed{x^2}

    2.1.2 Area of LMPQ =

  11. Identify the dimensions of rectangle LMPQ.

    Length LM=8LM = 8, Width LP=KQ=xLP = KQ = x.

  12. Calculate the area.

    Area of LMPQ =LM×LP=8×x=8x= LM \times LP = 8 \times x = \boxed{8x}

    2.1.3 Area of RQTS =

  13. Identify the dimensions of rectangle RQTS.

    Length RQ=KL=xRQ = KL = x, Width RS=5RS = 5.

  14. Calculate the area.

    Area of RQTS =RQ×RS=x×5=5x= RQ \times RS = x \times 5 = \boxed{5x}

    2.1.4 Area of QPTU =

  15. Identify the dimensions of rectangle QPTU.

    Length QP=LM=8QP = LM = 8, Width QT=RS=5QT = RS = 5.

  16. Calculate the area.

    Area of QPTU =QP×QT=8×5=40= QP \times QT = 8 \times 5 = \boxed{40}

    2.1.5 (x+8)(x+5)=(x+8)(x+5)=

  17. The product (x+8)(x+5)(x+8)(x+5) represents the total area of the large rectangle KLSU.

  18. Sum the areas of the four smaller rectangles calculated above.

    (x+8)(x+5)=Area of KLQR+Area of LMPQ+Area of RQTS+Area of QPTU(x+8)(x+5) = \text{Area of KLQR} + \text{Area of LMPQ} + \text{Area of RQTS} + \text{Area of QPTU} =x2+8x+5x+40= x^2 + 8x + 5x + 40
  19. Combine like terms.

    =x2+13x+40= \boxed{x^2 + 13x + 40}
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