Calculate the area of Fig 1.1.

We can divide Fig 1.1 into two rectangles:

• Rectangle 1: The top-left vertical part.
• Rectangle 2: The bottom-right horizontal part.

Rectangle 1 has a width of 4 cm and a height of 6 cm.
The area of Rectangle 1 ($A_1$) is:

$$A_1 = \text{width} \times \text{height} = 4 \text{ cm} \times 6 \text{ cm} = 24 \text{ cm}^2$$

Rectangle 2 has a height of 4 cm (given on the right side).
The total width of the figure is the sum of the top horizontal segment (4 cm) and the inner horizontal segment (6 cm).
Total width = $4 \text{ cm} + 6 \text{ cm} = 10 \text{ cm}$.
So, Rectangle 2 has a width of 10 cm and a height of 4 cm.
The area of Rectangle 2 ($A_2$) is:

$$A_2 = \text{width} \times \text{height} = 10 \text{ cm} \times 4 \text{ cm} = 40 \text{ cm}^2$$

The total area ($A_{\text{total}}$) is the sum of the areas of Rectangle 1 and Rectangle 2.

$$A_{\text{total}} = A_1 + A_2 = 24 \text{ cm}^2 + 40 \text{ cm}^2 = 64 \text{ cm}^2$$

The area of Fig 1.1 is $\boxed{\text{64 cm}^2}$.