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Calculate the area of rectangle A.

Mathematics

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3.2.1

  1. Calculate the area of rectangle A.

    Area A=length×width=100 cm×40 cm=4000 cm2\text{Area A} = \text{length} \times \text{width} = 100 \text{ cm} \times 40 \text{ cm} = 4000 \text{ cm}^2
  2. Calculate the area of rectangle B.

    Area B=length×width=120 cm×60 cm=7200 cm2\text{Area B} = \text{length} \times \text{width} = 120 \text{ cm} \times 60 \text{ cm} = 7200 \text{ cm}^2
  3. Calculate the total area in square centimeters.

    Total Area=Area A+Area B=4000 cm2+7200 cm2=11200 cm2\text{Total Area} = \text{Area A} + \text{Area B} = 4000 \text{ cm}^2 + 7200 \text{ cm}^2 = 11200 \text{ cm}^2
  4. Convert the total area from square centimeters to square meters.

    Since 1 m=100 cm1 \text{ m} = 100 \text{ cm}, then 1 m2=(100 cm)2=10000 cm21 \text{ m}^2 = (100 \text{ cm})^2 = 10000 \text{ cm}^2.

    Total Area in m2=11200 cm210000 cm2/m2=1.12 m2\text{Total Area in m}^2 = \frac{11200 \text{ cm}^2}{10000 \text{ cm}^2/\text{m}^2} = 1.12 \text{ m}^2

    The area of the shape of all boxes is 1.12 m2\boxed{\text{1.12 m}^2}.

    3.2.2

  5. Calculate the total area to be painted for two coats.

    The total area for one coat is 1.12 m21.12 \text{ m}^2 (from 3.2.1).

    Area for two coats=1.12 m2×2=2.24 m2\text{Area for two coats} = 1.12 \text{ m}^2 \times 2 = 2.24 \text{ m}^2
  6. Convert the volume of paint from milliliters to litres.

    500 ml=5001000 litres=0.5 litres500 \text{ ml} = \frac{500}{1000} \text{ litres} = 0.5 \text{ litres}
  7. Calculate the area that 0.5 litres0.5 \text{ litres} of paint can cover.

    Given that 1 litre1 \text{ litre} of paint covers 6.2 m26.2 \text{ m}^2.

    Area covered by 0.5 litres=0.5 litres×6.2 m2/litre=3.1 m2\text{Area covered by } 0.5 \text{ litres} = 0.5 \text{ litres} \times 6.2 \text{ m}^2/\text{litre} = 3.1 \text{ m}^2
  8. Compare the required area with the area the paint can cover.

    Required area for two coats = 2.24 m22.24 \text{ m}^2.
    Area covered by 500 ml500 \text{ ml} paint = 3.1 m23.1 \text{ m}^2.
    Since 3.1 m2>2.24 m23.1 \text{ m}^2 > 2.24 \text{ m}^2, the 500 ml500 \text{ ml} can of paint is sufficient to cover the shapes with two coats.

  9. Verify the salesman's statement.

    The salesman stated that a 500 ml500 \text{ ml} can is not enough. Our calculations show that it is enough.
    Therefore, the salesman's statement is incorrect\boxed{\text{incorrect}}.

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