Assuming IQ scores are normally distributed with a mean of 100 and a standard deviation of 14, what proportion of individuals would have an IQ of 100 or less?

The average (mean) intelligence of committee members is given as $\mu = 100$.
The standard deviation (SD) is given as $\sigma = 14$.
The distribution is assumed to be a normal distribution.

We need to find the proportion of women who would have an IQ of 100 or less. This can be written as $P(X \le 100)$, where $X$ is the IQ score.

For any normal distribution, the mean ($\mu$) is also the median. This means that exactly 50% of the data falls below the mean, and 50% of the data falls above the mean.
Therefore, the probability of a randomly selected value being less than or equal to the mean is 0.5.

In this case, $\mu = 100$.

The proportion of women expected to have an IQ of 100 or less is 0.5, or 50%.

The final answer is 0.5.