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Assumption: Physical dimensions like length and width must be positive. The given width (sqrt(2)-sqrt(7)) is negative since sqrt(2) ~= 1.414 and sqrt(7) ~= 2.646. Therefore, we w

Mathematics

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Assumption: Physical dimensions like length and width must be positive. The given width (2−7)(\sqrt{2}-\sqrt{7}) is negative since 2≈1.414\sqrt{2} \approx 1.414 and 7≈2.646\sqrt{7} \approx 2.646. Therefore, we will use the absolute value for the width: width=∣2−7∣=7−2\text{width} = |\sqrt{2}-\sqrt{7}| = \sqrt{7}-\sqrt{2} meters.
Assumption: The triangular section is a right-angled triangle, as the term "hypotenuse" is used.

a) Determine the area of the rectangular trench

Step 1: Simplify the expression for XX.
The length XX is given

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