This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
(i) Time taken to reach the maximum height Step 1: At maximum height, velocity v = 0 m/s. Equation of motion: v = u - g t Substitute v = 0 : 0 = u - g t u = g t 1 Step 2: Displacement h = 50 m. Equation: h = u t - (1)/(2) g t^2 Substitute u = g t from (1): 50 = (g t) t - (1)/(2) g t^2 50 = g t^2 - (1)/(2) g t^2 50 = (1)/(2) g t^2 Step 3: Substitute g = 10 m/s²: 50 = (1)/(2) × 10 × t^2 50 = 5 t^2 t^2 = 10 t = sqrt(10) \ s sqrt(10) \ s (ii) Speed of the throw From equation (1): u = g t Substitute g = 10 m/s² and t = sqrt(10) s: u = 10 × sqrt(10) = 10sqrt(10) \ m/s Alternatively, using v^2 = u^2 - 2 g h : 0 = u^2 - 2 × 10 × 50 u^2 = 1000 u = sqrt(1000) = sqrt(100 × 10) = 10sqrt(10) \ m/s 10sqrt(10) \ m/s