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b). find e rate values of a anb ine 13. sqrt(a+bi) = 2+3i

Mathematics

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Answer

a=−5,b=12a = -5, b = 12

Step-by-step solution

3 steps

To find the values of aa and bb, we will square both sides of the given equation and then equate the real and imaginary parts.

  1. Square both sides of the equation.

    a+bi=2+3i\sqrt{a+bi} = 2+3i (a+bi)2=(2+3i)2(\sqrt{a+bi})^2 = (2+3i)^2 a+bi=(2+3i)(2+3i)a+bi = (2+3i)(2+3i)
  2. Expand the right side of the equation.

    a+bi=2(2)+2(3i)+3i(2)+3i(3i)a+bi = 2(2) + 2(3i) + 3i(2) + 3i(3i) a+bi=4+6i+6i+9i2a+bi = 4 + 6i + 6i + 9i^2

    Since i2=−1i^2 = -1:

    a+bi=4+12i+9(−1)a+bi = 4 + 12i + 9(-1) a+bi=4+12i−9a+bi = 4 + 12i - 9 a+bi=(4−9)+12ia+bi = (4-9) + 12i a+bi=−5+12ia+bi = -5 + 12i
  3. Equate the real and imaginary parts.

    For two complex numbers to be equal, their real parts must be equal and their imaginary parts must be equal.
    Comparing the real parts:

    a=−5a = -5

    Comparing the imaginary parts:

    b=12b = 12

    The values are:

    a=−5,b=12a = -5, b = 12
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